Factor completely [tex]$16x^2 + 40x + 25$[/tex]:

A. [tex]$(4x - 5)(4x - 5)$[/tex]
B. [tex][tex]$(2x - 5)(2x - 5)$[/tex][/tex]
C. [tex]$(2x + 5)(2x + 5)$[/tex]
D. [tex]$(4x + 5)(4x + 5)$[/tex]



Answer :

To factor the polynomial [tex]\(16x^2 + 40x + 25\)[/tex] completely, we need to find factors that multiply to give the polynomial. Let's proceed step-by-step:

1. Identify the given polynomial:
The polynomial given is [tex]\(16x^2 + 40x + 25\)[/tex].

2. Identify the coefficients:
- The coefficient of [tex]\(x^2\)[/tex] is [tex]\(16\)[/tex].
- The coefficient of [tex]\(x\)[/tex] is [tex]\(40\)[/tex].
- The constant term is [tex]\(25\)[/tex].

3. Find the factors:
To factor this polynomial, we need to look for two binomials that multiply to give back the original quadratic polynomial:
[tex]\[ (ax + b)(cx + d) \][/tex]

4. Trial and error (or inspection) to find suitable factors (or using a more systematic approach):
We look for numbers that multiply to give the product of the leading coefficient (16) and the constant term (25). The product is [tex]\(16 \times 25 = 400\)[/tex].

5. Identify pairs:
Let's find a pair of factors [tex]\( (ax + b) \)[/tex] and [tex]\( (cx + d) \)[/tex] whose cross-multiplication gives the middle term 40x. Notice that the pair:
[tex]\[ (4x + 5)\text{ and }(4x + 5) \][/tex]
works because:
[tex]\[ (4x + 5)(4x + 5) = 16x^2 + 20x + 20x + 25 = 16x^2 + 40x + 25 \][/tex]

6. Verify the factors:
[tex]\((4x + 5)^2 = (4x + 5)(4x + 5)\)[/tex]
Expanding this:
[tex]\[ (4x + 5)(4x + 5) = 16x^2 + 20x + 20x + 25 = 16x^2 + 40x + 25 \][/tex]

Thus, the polynomial [tex]\(16x^2 + 40x + 25\)[/tex] factors completely as:

[tex]\[ (4x + 5)^2 \text{ or } (4x + 5)(4x + 5). \][/tex]

Therefore, the correct factored form from the given choices is:
[tex]\[ (4x + 5)(4x + 5) \][/tex]