An ellipse has a center at the origin, a vertex along the major axis at [tex] (20,0) [/tex], and a focus at [tex] (c,0) [/tex]. The equation of the ellipse is in the form below:

[tex]\[
\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1
\][/tex]

What is the value of [tex] b [/tex] in the equation?

A. 12
B. 16
C. 20
D. 24



Answer :

To find the value of [tex]\( b \)[/tex] in the equation of an ellipse given the distance to a vertex and a focus, we start with the following pieces of information:

- The distance to the vertex along the major axis is represented by [tex]\( a \)[/tex]. Given [tex]\( a = 20 \)[/tex].
- The distance from the center to the focus is represented by [tex]\( c \)[/tex]. Given [tex]\( c = 16 \)[/tex].

The relationship between [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex] for an ellipse is given by:
[tex]\[ c^2 = a^2 - b^2 \][/tex]

First, we calculate [tex]\( a^2 \)[/tex]:
[tex]\[ a^2 = 20^2 = 400 \][/tex]

Next, we calculate [tex]\( c^2 \)[/tex]:
[tex]\[ c^2 = 16^2 = 256 \][/tex]

Using the relationship [tex]\( c^2 = a^2 - b^2 \)[/tex], we solve for [tex]\( b^2 \)[/tex]:
[tex]\[ b^2 = a^2 - c^2 \][/tex]
[tex]\[ b^2 = 400 - 256 \][/tex]
[tex]\[ b^2 = 144 \][/tex]

To find [tex]\( b \)[/tex], we take the square root of [tex]\( b^2 \)[/tex]:
[tex]\[ b = \sqrt{144} = 12 \][/tex]

So, the value of [tex]\( b \)[/tex] in the equation is:
[tex]\[ 12 \][/tex]

Hence, the correct answer is [tex]\( \boxed{12} \)[/tex].