Answer :
Certainly! Let's go through the solution step-by-step for this question.
Given:
[tex]\[ PCH_3OH = 107.0 \text{ mmHg} \][/tex]
To solve this question:
1. We need to identify that [tex]\( PCH_3OH \)[/tex] is the vapor pressure of methanol ([tex]\( CH_3OH \)[/tex]) at a certain temperature.
2. The problem states that the vapor pressure of methanol at this specific condition is [tex]\( 107.0 \text{ mmHg} \)[/tex].
3. Since we are directly given the vapor pressure value, we can conclude that the vapor pressure of methanol, [tex]\( PCH_3OH \)[/tex], is [tex]\( 107.0 \text{ mmHg} \)[/tex].
So, the answer to the problem, in this context, is simply:
[tex]\[ \boxed{107.0 \text{ mmHg}} \][/tex]
This tells us that under the conditions specified in the question, the vapor pressure of methanol ([tex]\( CH_3OH \)[/tex]) is [tex]\( 107.0 \text{ mmHg} \)[/tex].
Given:
[tex]\[ PCH_3OH = 107.0 \text{ mmHg} \][/tex]
To solve this question:
1. We need to identify that [tex]\( PCH_3OH \)[/tex] is the vapor pressure of methanol ([tex]\( CH_3OH \)[/tex]) at a certain temperature.
2. The problem states that the vapor pressure of methanol at this specific condition is [tex]\( 107.0 \text{ mmHg} \)[/tex].
3. Since we are directly given the vapor pressure value, we can conclude that the vapor pressure of methanol, [tex]\( PCH_3OH \)[/tex], is [tex]\( 107.0 \text{ mmHg} \)[/tex].
So, the answer to the problem, in this context, is simply:
[tex]\[ \boxed{107.0 \text{ mmHg}} \][/tex]
This tells us that under the conditions specified in the question, the vapor pressure of methanol ([tex]\( CH_3OH \)[/tex]) is [tex]\( 107.0 \text{ mmHg} \)[/tex].