To identify the base and conjugate base in the given chemical equation:
[tex]\[ HSO_4^{-1}(aq) + C_2O_4^{-2}(aq) \leftrightarrow SO_4^{-2}(aq) + HC_2O_4^{-1}(aq) \][/tex]
We need to analyze the behavior of each species involved in the reaction in terms of proton (H[tex]\(^+\)[/tex]) donation and acceptance.
1. Identify Proton Donation and Acceptance:
- [tex]\(C_2O_4^{-2}(aq)\)[/tex] transforms into [tex]\(HC_2O_4^{-1}(aq)\)[/tex]. This transformation indicates that [tex]\(C_2O_4^{-2}\)[/tex] accepts a proton (H[tex]\(^+\)[/tex]) to become [tex]\(HC_2O_4^{-1}\)[/tex]. Therefore, [tex]\(C_2O_4^{-2}\)[/tex] is a base and [tex]\(HC_2O_4^{-1}\)[/tex] is its conjugate acid.
- [tex]\(HSO_4^{-1}(aq)\)[/tex] transforms into [tex]\(SO_4^{-2}(aq)\)[/tex]. This transformation indicates that [tex]\(HSO_4^{-1}\)[/tex] donates a proton to become [tex]\(SO_4^{-2}\)[/tex]. Therefore, [tex]\(HSO_4^{-1}\)[/tex] is an acid and [tex]\(SO_4^{-2}\)[/tex] is its conjugate base.
2. Match with Options:
- [tex]\(C_2O_4^{-2}(aq)\)[/tex] is the base because it accepts a proton.
- [tex]\(HC_2O_4^{-1}(aq)\)[/tex] is not the conjugate base of [tex]\(C_2O_4^{-2}\)[/tex], it is instead the conjugate acid.
- [tex]\(HSO_4^{-1}(aq)\)[/tex] is not the base, as it donates a proton.
- [tex]\(SO_4^{-2}(aq)\)[/tex] is the conjugate base of [tex]\(HSO_4^{-1}(aq)\)[/tex].
Therefore, the correct answer is:
[tex]\[ \text{HSO}_4^{-1} \text{(aq)} \text{ is the base, SO}_4^{-2} \text{(aq)} \text{ is the conjugate base.} \][/tex]
This corresponds to the correct option:
[tex]\[ \text{HSO}_4^{-1} \text{(aq)} \text{ is the base, SO}_4^{-2} \text{(aq)} \text{ is the conjugate base.} \][/tex]
