Determine which integer in the solution set will make the equation true.

[tex]\[
\begin{array}{l}
3p + 13 = 22 \\
S: \{-1, 1, 3, 4\}
\end{array}
\][/tex]

A. -1
B. 1
C. 3
D. 4



Answer :

To determine which integer from the set [tex]\( S = \{-1, 1, 3, 4\} \)[/tex] will make the equation [tex]\( 3p + 13 = 22 \)[/tex] true, let’s go through each step in detail.

Step 1: Start with the equation and isolate [tex]\( p \)[/tex]:
[tex]\[ 3p + 13 = 22 \][/tex]

Step 2: Subtract 13 from both sides of the equation to isolate the term with [tex]\( p \)[/tex]:
[tex]\[ 3p + 13 - 13 = 22 - 13 \][/tex]
This simplifies to:
[tex]\[ 3p = 9 \][/tex]

Step 3: Divide both sides by 3 to solve for [tex]\( p \)[/tex]:
[tex]\[ p = \frac{9}{3} = 3 \][/tex]

Step 4: Now, we need to check the values in the given set [tex]\( S = \{-1, 1, 3, 4\} \)[/tex].

Check each element:

- For [tex]\( p = -1 \)[/tex]:
[tex]\[ 3(-1) + 13 = -3 + 13 = 10 \quad (\text{not equal to } 22) \][/tex]

- For [tex]\( p = 1 \)[/tex]:
[tex]\[ 3(1) + 13 = 3 + 13 = 16 \quad (\text{not equal to } 22) \][/tex]

- For [tex]\( p = 3 \)[/tex]:
[tex]\[ 3(3) + 13 = 9 + 13 = 22 \quad (\text{equal to } 22) \][/tex]

- For [tex]\( p = 4 \)[/tex]:
[tex]\[ 3(4) + 13 = 12 + 13 = 25 \quad (\text{not equal to } 22) \][/tex]

Upon checking each value in [tex]\( S \)[/tex], we see that the only integer that satisfies the equation [tex]\( 3p + 13 = 22 \)[/tex] is [tex]\( p = 3 \)[/tex].

Therefore, the integer in the solution set that makes the equation true is [tex]\( 3 \)[/tex].