What is the solution to the equation below expressed as a logarithm?

[tex]\[
\begin{aligned}
6 \cdot 2^{8t} & = 24 \\
t & = \frac{\log_2(4)}{8} \quad t = 8 \log_2(4)
\end{aligned}
\][/tex]

A.

B.

[tex]\[
t = \frac{\log_2(8)}{4} \quad t = 4 \log_2(8)
\][/tex]



Answer :

Sure, let's solve the equation [tex]\( 6 \cdot 2^{8t} = 24 \)[/tex] step-by-step.

1. Original Equation:
[tex]\[ 6 \cdot 2^{8t} = 24 \][/tex]

2. Isolate the exponential term:
Divide both sides of the equation by 6:
[tex]\[ 2^{8t} = \frac{24}{6} \][/tex]
Simplifying the right-hand side:
[tex]\[ 2^{8t} = 4 \][/tex]

3. Express 4 as a power of 2:
Note that [tex]\( 4 = 2^2 \)[/tex]:
[tex]\[ 2^{8t} = 2^2 \][/tex]

4. Equate the exponents:
Since the bases are the same, the exponents must be equal:
[tex]\[ 8t = 2 \][/tex]

5. Solve for [tex]\( t \)[/tex]:
Divide both sides of the equation by 8:
[tex]\[ t = \frac{2}{8} \][/tex]
Simplify the fraction:
[tex]\[ t = \frac{1}{4} \][/tex]

6. Express [tex]\( t \)[/tex] as a logarithm:
Recall that [tex]\( 2^{8t} = 2^2 \)[/tex] can be expressed in logarithmic form:
[tex]\[ 8t = \log_2(4) \][/tex]

Therefore,
[tex]\[ t = \frac{\log_2(4)}{8} \][/tex]

So, the detailed step-by-step solution to the equation [tex]\( 6 \cdot 2^{8t} = 24 \)[/tex] expressed as a logarithm is:
[tex]\[ t = \frac{\log_2(4)}{8} \][/tex]

Therefore, the correct answer is:
[tex]\( t = \frac{\log_2(4)}{8} \)[/tex].