Solve the quadratic equation by taking square roots. Write your answer with no spaces as [tex]$x = a, -a$[/tex], where [tex]$a$[/tex] and [tex][tex]$-a$[/tex][/tex] are the values you found when solving. Round to the nearest tenth.

[tex]
2x^2 - 9 = 121
[/tex]

[tex]\square[/tex]



Answer :

To solve the quadratic equation [tex]\(2x^2 - 9 = 121\)[/tex] by taking square roots, follow these step-by-step instructions:

1. Isolate the quadratic term:
[tex]\[ 2x^2 - 9 = 121 \][/tex]
Add 9 to both sides:
[tex]\[ 2x^2 - 9 + 9 = 121 + 9 \][/tex]
Simplifying, we get:
[tex]\[ 2x^2 = 130 \][/tex]

2. Solve for [tex]\(x^2\)[/tex]:
Divide both sides by 2:
[tex]\[ x^2 = \frac{130}{2} \][/tex]
Simplifying, we have:
[tex]\[ x^2 = 65 \][/tex]

3. Take the square root of both sides to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \pm \sqrt{65} \][/tex]

4. Calculate the numerical values:
Find the square root of 65 and round to the nearest tenth:
[tex]\[ \sqrt{65} \approx 8.1 \][/tex]

So, the two solutions for [tex]\(x\)[/tex] are:
[tex]\[ x = 8.1 \quad \text{and} \quad x = -8.1 \][/tex]

Therefore, the answer in the required format, with no spaces, is:
[tex]\[ x = 8.1,-8.1 \][/tex]