Solve the equation using square roots.

[tex]\[ x^2 + 10 = 9 \][/tex]

A. [tex]\(-1\)[/tex]

B. no real number solutions

C. [tex]\(\pm \sqrt{1}\)[/tex]

D. 1



Answer :

Let's solve the equation [tex]\( x^2 + 10 = 9 \)[/tex] step by step.

1. First, isolate the [tex]\( x^2 \)[/tex] term by subtracting 10 from both sides of the equation.
[tex]\[ x^2 + 10 - 10 = 9 - 10 \][/tex]
This simplifies to:
[tex]\[ x^2 = -1 \][/tex]

2. Next, we take the square root of both sides to solve for [tex]\( x \)[/tex].
[tex]\[ x = \pm \sqrt{-1} \][/tex]

3. The square root of [tex]\(-1\)[/tex] is not a real number. In the real number system, the square root of a negative number does not exist. Therefore, we say there are no real number solutions to this equation.

Thus, the equation [tex]\( x^2 + 10 = 9 \)[/tex] has no real number solutions.