Use the drawing tool to form the correct answers on the provided graph.

A student observes that the motion of a weight oscillating up and down on a spring can be modeled by the following equation, where [tex]$h$[/tex] is the weight's height above the ground, in meters, and [tex]$t$[/tex] is the time, in seconds.

[tex]\[ h(t) = 0.5 \cdot \sin \left(\pi t + \frac{\pi}{2}\right) + 1 \][/tex]

On the graph, plot the points where the height [tex]$h(t)$[/tex] is at a maximum.



Answer :

To find the points where the height [tex]\( h(t) \)[/tex] of the weight on the spring is at a maximum, follow these steps:

1. Understand the given function:
The height function given is:
[tex]\[ h(t) = 0.5 \cdot \sin \left(\pi t + \frac{\pi}{2}\right) + 1 \][/tex]

2. Analyze the sine function:
The sine function [tex]\(\sin(\theta)\)[/tex] has a maximum value of 1. We need to find the values of [tex]\( t \)[/tex] for which:
[tex]\[ \sin\left(\pi t + \frac{\pi}{2}\right) = 1 \][/tex]
This equation is true when:
[tex]\[ \pi t + \frac{\pi}{2} = \frac{\pi}{2} + 2k\pi \quad \text{where} \; k \; \text{is an integer} \][/tex]
Simplifying gives:
[tex]\[ \pi t = 2k\pi \implies t = 2k \][/tex]

3. Identify specific maximum points:
Some specific values of [tex]\( t \)[/tex] where [tex]\( t = 2k \)[/tex] would be:
[tex]\[ t = 0, 2, 4, \ldots \][/tex]

4. Calculate the maximum height:
Substituting these [tex]\( t \)[/tex] values back into the height function [tex]\( h(t) \)[/tex], we get:
[tex]\[ h(t) = 0.5 \cdot 1 + 1 = 1.5 \][/tex]

5. Maximum height points:
Therefore, the points where height [tex]\( h(t) \)[/tex] is at a maximum are:
[tex]\[ (0, 1.5), (2, 1.5), (4, 1.5), \ldots \][/tex]

Using these steps, you should plot the points (0, 1.5), (2, 1.5), (4, 1.5), etc., on the given graph to show the points where the weight is at its maximum height above the ground.