Let's translate and understand the problem first.
The question appears to be somewhat garbled, but we can attempt to follow the general format and recognize some familiar notations and requirements.
Given:
- [tex]\(l = ?\)[/tex] (we need to find this value, assuming it refers to a quantity or measurement)
- [tex]\(m^3 c = 8\)[/tex] (assuming some cubic measurement)
- Seran 15 alibes (assuming some units or items)
Now, let's construct the steps:
1. Initial setup:
- The initial quantity of a certain item (which could be money, volume, mass, etc.) is set.
- We will need to find out the expenditure or conversion based on given conditions.
Given clue:
- An initial quantity of 23 units.
- The cost per unit or conversion factor is 3 units.
- Quantity of items (or instances of a conversion) is 5.
2. Calculate expenditures:
- Total expenditures = Quantity of items × Cost per unit
- Let's denote the total expenditures as [tex]\(E\)[/tex].
3. Calculate remaining quantity:
- Remaining quantity = Initial quantity - Total expenditures
- Let's denote the remaining quantity as [tex]\(R\)[/tex].
Let's break down the solution step-by-step:
### Step-by-Step Solution
1. Initial Quantities:
- Initial quantity ([tex]\(Q_{\text{initial}}\)[/tex]): 23 units.
- Number of quantities ([tex]\(n_{\text{items}}\)[/tex]): 5 items.
- Cost per quantity ([tex]\(C_{\text{per unit}}\)[/tex]): 3 units.
2. Calculate Total Expenditures:
- Total expenditures, [tex]\(E\)[/tex]:
[tex]\[
E = n_{\text{items}} \times C_{\text{per unit}}
\][/tex]
Substituting the values:
[tex]\[
E = 5 \times 3 = 15 \text{ units}
\][/tex]
3. Calculate Remaining Quantity:
- Remaining quantity, [tex]\(R\)[/tex]:
[tex]\[
R = Q_{\text{initial}} - E
\][/tex]
Substituting the values:
[tex]\[
R = 23 - 15 = 8 \text{ units}
\][/tex]
The results are:
- Total expenditures = 15 units.
- Remaining quantity = 8 units.
Therefore:
- The amount spent (or whatever it is referred to in the specific context, usually could be cost incurred or volume converted, etc.) is 15 units.
- The amount left (which could be remaining money or volume left) is 8 units.
These numerical results (15 and 8) provide a clear outcome for the given problem scenario, filling in the blanks for where values were sought.
