To determine the probability of drawing a ball that is not white from the bag, let's break down the problem step-by-step:
1. Determine the total number of balls in the bag:
- Red balls: 4
- White balls: 6
- Green balls: 3
Added together, the total number of balls is:
[tex]\[
4 + 6 + 3 = 13
\][/tex]
So, there are 13 balls in total.
2. Determine the number of balls that are not white:
- The balls that are not white include the red and green balls.
- Red balls: 4
- Green balls: 3
Added together, the number of non-white balls is:
[tex]\[
4 + 3 = 7
\][/tex]
So, there are 7 non-white balls.
3. Calculate the probability:
- Probability is defined as the number of favorable outcomes divided by the total number of possible outcomes.
- The favorable outcome here is drawing a non-white ball, which is 7.
- The total number of possible outcomes is the total number of balls, which is 13.
Therefore, the probability [tex]\( P \)[/tex] of drawing a non-white ball is:
[tex]\[
P(\text{non-white}) = \frac{\text{number of non-white balls}}{\text{total number of balls}} = \frac{7}{13}
\][/tex]
Given this calculation, the correct answer is:
[tex]\[
\boxed{\frac{7}{13}}
\][/tex]
Thus, the answer to the question is B. [tex]$\frac{7}{13}$[/tex].
