Answer :
To determine if the events [tex]\( N \)[/tex] (testing negative for the flu) and [tex]\( V \)[/tex] (being vaccinated) are independent, we need to calculate the following probabilities:
1. [tex]\( P(N \mid V) \)[/tex]: The probability of testing negative given that a person is vaccinated.
2. [tex]\( P(N) \)[/tex]: The overall probability of testing negative.
We'll start by computing these probabilities step-by-step using the information provided in the two-way table.
### Step 1: Calculate [tex]\( P(N \mid V) \)[/tex]
[tex]\( P(N \mid V) \)[/tex] is the conditional probability that a person tested negative given that they were vaccinated.
To compute [tex]\( P(N \mid V) \)[/tex]:
[tex]\[ P(N \mid V) = \frac{\text{Number of vaccinated people who tested negative}}{\text{Total number of vaccinated people}} \][/tex]
From the table:
- Number of vaccinated people who tested negative (Negative test among vaccinated) = 771
- Total number of vaccinated people (Vaccinated) = 1236
Thus:
[tex]\[ P(N \mid V) = \frac{771}{1236} \][/tex]
Rounding the result to the nearest hundredth:
[tex]\[ P(N \mid V) = 0.62 \][/tex]
### Step 2: Calculate [tex]\( P(N) \)[/tex]
[tex]\( P(N) \)[/tex] is the overall probability that a person tested negative, regardless of vaccination status.
To compute [tex]\( P(N) \)[/tex]:
[tex]\[ P(N) = \frac{\text{Number of people who tested negative}}{\text{Total number of people}} \][/tex]
From the table:
- Number of people who tested negative (Total negative cases) = 1371
- Total number of people (Total) = 2321
Thus:
[tex]\[ P(N) = \frac{1371}{2321} \][/tex]
Rounding the result to the nearest hundredth:
[tex]\[ P(N) = 0.59 \][/tex]
### Step 3: Determine Independence
Events [tex]\( N \)[/tex] and [tex]\( V \)[/tex] are independent if:
[tex]\[ P(N \mid V) = P(N) \][/tex]
Comparing the two probabilities we calculated:
- [tex]\( P(N \mid V) = 0.62 \)[/tex]
- [tex]\( P(N) = 0.59 \)[/tex]
Since [tex]\( P(N \mid V) \neq P(N) \)[/tex], events [tex]\( N \)[/tex] and [tex]\( V \)[/tex] are not independent.
### Final Answers
- [tex]\( P(N \mid V) = 0.62 \)[/tex]
- [tex]\( P(N) = 0.59 \)[/tex]
- Are events [tex]\( N \)[/tex] and [tex]\( V \)[/tex] independent? No
1. [tex]\( P(N \mid V) \)[/tex]: The probability of testing negative given that a person is vaccinated.
2. [tex]\( P(N) \)[/tex]: The overall probability of testing negative.
We'll start by computing these probabilities step-by-step using the information provided in the two-way table.
### Step 1: Calculate [tex]\( P(N \mid V) \)[/tex]
[tex]\( P(N \mid V) \)[/tex] is the conditional probability that a person tested negative given that they were vaccinated.
To compute [tex]\( P(N \mid V) \)[/tex]:
[tex]\[ P(N \mid V) = \frac{\text{Number of vaccinated people who tested negative}}{\text{Total number of vaccinated people}} \][/tex]
From the table:
- Number of vaccinated people who tested negative (Negative test among vaccinated) = 771
- Total number of vaccinated people (Vaccinated) = 1236
Thus:
[tex]\[ P(N \mid V) = \frac{771}{1236} \][/tex]
Rounding the result to the nearest hundredth:
[tex]\[ P(N \mid V) = 0.62 \][/tex]
### Step 2: Calculate [tex]\( P(N) \)[/tex]
[tex]\( P(N) \)[/tex] is the overall probability that a person tested negative, regardless of vaccination status.
To compute [tex]\( P(N) \)[/tex]:
[tex]\[ P(N) = \frac{\text{Number of people who tested negative}}{\text{Total number of people}} \][/tex]
From the table:
- Number of people who tested negative (Total negative cases) = 1371
- Total number of people (Total) = 2321
Thus:
[tex]\[ P(N) = \frac{1371}{2321} \][/tex]
Rounding the result to the nearest hundredth:
[tex]\[ P(N) = 0.59 \][/tex]
### Step 3: Determine Independence
Events [tex]\( N \)[/tex] and [tex]\( V \)[/tex] are independent if:
[tex]\[ P(N \mid V) = P(N) \][/tex]
Comparing the two probabilities we calculated:
- [tex]\( P(N \mid V) = 0.62 \)[/tex]
- [tex]\( P(N) = 0.59 \)[/tex]
Since [tex]\( P(N \mid V) \neq P(N) \)[/tex], events [tex]\( N \)[/tex] and [tex]\( V \)[/tex] are not independent.
### Final Answers
- [tex]\( P(N \mid V) = 0.62 \)[/tex]
- [tex]\( P(N) = 0.59 \)[/tex]
- Are events [tex]\( N \)[/tex] and [tex]\( V \)[/tex] independent? No