To answer the question involving the identification of compounds, it's important to first correct any apparent typographical errors and then interpret the given molecular structures accurately.
4) Give the IUPAC name of the following compounds:
(a) [tex]\( \text{Cl}_3 \text{CH} = \text{CHCH}_2 \text{CH}_2 \text{C} = \text{CH} \)[/tex]
(b) [tex]\( \text{HC} \equiv \text{CCH}_2 \text{CH}_3 \text{CH} = \text{CH}_2 \)[/tex]
(i) [tex]\( \text{H}_3 \text{C}-\text{CH}(\text{CH}_3)-\text{CH}_2-\text{CH}_3 \)[/tex]
### Detailed Solutions
(a) [tex]\( \text{Cl}_3 \text{CH} = \text{CHCH}_2 \text{CH}_2 \text{C} = \text{CH} \)[/tex]
1. Identify the longest carbon chain that includes the double bonds:
- The longest chain contains 6 carbon atoms, including both double bonds.
2. Number the chain:
- Begin numbering from the end nearest to the first double bond to get the lowest possible locants for the double bonds.
- Here, numbering from left to right:
1. [tex]\(\text{Cl}_3 \text{C}=\text{CH}-\text{CH}_2-\text{CH}_2-\text{CH}=\text{CH}\)[/tex]
- Numbering gives positions for double bonds at carbons 1 and 5.
3. Identify and name substituents:
- There is a trichloromethyl group ([tex]\(\text{Cl}_3 \text{C}-\)[/tex]) at the first carbon.
4. Combine the name:
- The parent chain is a hexadiene as there are 6 carbons and 2 double bonds.
- IUPAC name: 1-(Trichloromethyl)-1,5-hexadiene
(b) [tex]\( \text{HC} \equiv \text{CCH}_2 \text{CH}_3 \text{CH} = \text{CH}_2 \)[/tex]
1. Identify the longest carbon chain that includes the triple bond and double bond:
- The longest chain contains 6 carbon atoms, including both multiple bonds.
2. Number the chain:
- Numbering starts from the end nearest to the highest priority functional group. In this case, triple bonds have priority to double bonds.
- So, numbering from left to right:
1. [tex]\(\text{HC} \equiv \text{C}-\text{CH}_2-\text{CH}_2-\text{CH}=\text{CH}_2\)[/tex]
- Numbering gives positions for the triple bond at carbon 1 and the double bond at carbon 5.
3. Identify and name substituents:
- There are no additional substituents.
4. Combine the name:
- The parent chain is a hexene-yne.
- IUPAC name: Hex-5-en-1-yne
(i) [tex]\( \text{H}_3 \text{C}-\text{CH}(\text{CH}_3)-\text{CH}_2-\text{CH}_3 \)[/tex]
1. Identify the longest carbon chain:
- The longest chain contains 4 carbon atoms.
2. Number the chain:
- Numbering from left to right, providing the lowest locant for the substituent:
1. [tex]\(\text{H}_3 \text{C}-\text{CH}(\text{CH}_3)-\text{CH}_2-\text{CH}_3\)[/tex]
- Methyl group at carbon 2.
- Numbering gives locant 2 for the methyl substituent.
3. Identify and name substituents:
- There is a methyl group at the second carbon (2-methyl).
4. Combine the name:
- The parent chain is butane.
- IUPAC name: 2-Methylbutane
