A golf ball, thrown upwards, rises at a speed of [tex]v[/tex] meters per second. The ball reaches a maximum height of [tex]h[/tex] meters.

[tex]h[/tex] is proportional to the square of [tex]v[/tex].

When [tex]v = 20[/tex], [tex]h = 8[/tex].

Work out the maximum height reached by the golf ball when [tex]v = 35[/tex].



Answer :

Certainly! Let's solve this step by step.

To determine the maximum height reached by the golf ball, we start with the given relationship:

[tex]\[ h \text{ is proportional to } v^2 \][/tex]

This can be written mathematically as:

[tex]\[ h = k \cdot v^2 \][/tex]

where [tex]\( k \)[/tex] is the proportionality constant.

First, we need to determine the value of [tex]\( k \)[/tex] using the initial information provided:

[tex]\[ v = 20 \, \text{m/s}, \, h = 8 \, \text{m} \][/tex]

Substituting these values into the equation:

[tex]\[ 8 = k \cdot (20)^2 \][/tex]

[tex]\[ 8 = k \cdot 400 \][/tex]

Solving for [tex]\( k \)[/tex]:

[tex]\[ k = \frac{8}{400} \][/tex]

[tex]\[ k = 0.02 \][/tex]

Now that we have found the proportionality constant [tex]\( k \)[/tex], we can use it to find the maximum height [tex]\( h \)[/tex] when the speed [tex]\( v \)[/tex] is 35 m/s:

[tex]\[ v = 35 \, \text{m/s} \][/tex]

Using our equation again:

[tex]\[ h = k \cdot v^2 \][/tex]

Substituting [tex]\( k \)[/tex] and [tex]\( v \)[/tex]:

[tex]\[ h = 0.02 \cdot (35)^2 \][/tex]

[tex]\[ h = 0.02 \cdot 1225 \][/tex]

[tex]\[ h = 24.5 \, \text{m} \][/tex]

Therefore, the maximum height reached by the golf ball when its speed is 35 m/s is 24.5 meters.