Jasmine wants to paint two of her bedroom walls. The ceiling is 8 feet high. One wall is 18 feet in length, but it has a French door measuring 5 feet wide and 7 feet tall. The other wall is 15 feet in length and has a large window measuring 6 feet wide and 3 feet tall. The door and the window are not paintable.

\begin{tabular}{|c|c|}
\hline
Column A & Column B \\
\hline
\begin{tabular}{l}
The paintable area of the wall with \\
the door
\end{tabular} &
\begin{tabular}{l}
The paintable area of the wall with the \\
window
\end{tabular} \\
\hline
\end{tabular}

Choose the statement about column A and column B that is true.

A. The area in column A is greater.

B. The area in column [tex]$B$[/tex] is greater.

C. The two areas are equal.

D. The relationship cannot be determined.

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Answer :

Let's begin by understanding the dimensions and areas involved for each wall.

### Wall with the Door
1. Height of the wall: 8 feet
2. Length of the wall: 18 feet
3. Total area of the wall:
[tex]\[ \text{Total area} = \text{height} \times \text{length} = 8 \, \text{ft} \times 18 \, \text{ft} = 144 \, \text{square feet} \][/tex]

4. Dimensions of the door: 5 feet wide and 7 feet tall
5. Area of the door:
[tex]\[ \text{Door area} = \text{width} \times \text{height} = 5 \, \text{ft} \times 7 \, \text{ft} = 35 \, \text{square feet} \][/tex]

6. Paintable area of the wall with the door:
[tex]\[ \text{Paintable area} = \text{Total area} - \text{Door area} = 144 \, \text{square feet} - 35 \, \text{square feet} = 109 \, \text{square feet} \][/tex]

### Wall with the Window
1. Height of the wall: 8 feet
2. Length of the wall: 15 feet
3. Total area of the wall:
[tex]\[ \text{Total area} = \text{height} \times \text{length} = 8 \, \text{ft} \times 15 \, \text{ft} = 120 \, \text{square feet} \][/tex]

4. Dimensions of the window: 6 feet wide and 3 feet tall
5. Area of the window:
[tex]\[ \text{Window area} = \text{width} \times \text{height} = 6 \, \text{ft} \times 3 \, \text{ft} = 18 \, \text{square feet} \][/tex]

6. Paintable area of the wall with the window:
[tex]\[ \text{Paintable area} = \text{Total area} - \text{Window area} = 120 \, \text{square feet} - 18 \, \text{square feet} = 102 \, \text{square feet} \][/tex]

### Comparison:
- Paintable area of the wall with the door: 109 square feet
- Paintable area of the wall with the window: 102 square feet

Since 109 square feet (paintable area of the wall with the door) is greater than 102 square feet (paintable area of the wall with the window):

The true statement about column A and column B is:
- A. The area in column A is greater.