Answer :
Let's begin by understanding the dimensions and areas involved for each wall.
### Wall with the Door
1. Height of the wall: 8 feet
2. Length of the wall: 18 feet
3. Total area of the wall:
[tex]\[ \text{Total area} = \text{height} \times \text{length} = 8 \, \text{ft} \times 18 \, \text{ft} = 144 \, \text{square feet} \][/tex]
4. Dimensions of the door: 5 feet wide and 7 feet tall
5. Area of the door:
[tex]\[ \text{Door area} = \text{width} \times \text{height} = 5 \, \text{ft} \times 7 \, \text{ft} = 35 \, \text{square feet} \][/tex]
6. Paintable area of the wall with the door:
[tex]\[ \text{Paintable area} = \text{Total area} - \text{Door area} = 144 \, \text{square feet} - 35 \, \text{square feet} = 109 \, \text{square feet} \][/tex]
### Wall with the Window
1. Height of the wall: 8 feet
2. Length of the wall: 15 feet
3. Total area of the wall:
[tex]\[ \text{Total area} = \text{height} \times \text{length} = 8 \, \text{ft} \times 15 \, \text{ft} = 120 \, \text{square feet} \][/tex]
4. Dimensions of the window: 6 feet wide and 3 feet tall
5. Area of the window:
[tex]\[ \text{Window area} = \text{width} \times \text{height} = 6 \, \text{ft} \times 3 \, \text{ft} = 18 \, \text{square feet} \][/tex]
6. Paintable area of the wall with the window:
[tex]\[ \text{Paintable area} = \text{Total area} - \text{Window area} = 120 \, \text{square feet} - 18 \, \text{square feet} = 102 \, \text{square feet} \][/tex]
### Comparison:
- Paintable area of the wall with the door: 109 square feet
- Paintable area of the wall with the window: 102 square feet
Since 109 square feet (paintable area of the wall with the door) is greater than 102 square feet (paintable area of the wall with the window):
The true statement about column A and column B is:
- A. The area in column A is greater.
### Wall with the Door
1. Height of the wall: 8 feet
2. Length of the wall: 18 feet
3. Total area of the wall:
[tex]\[ \text{Total area} = \text{height} \times \text{length} = 8 \, \text{ft} \times 18 \, \text{ft} = 144 \, \text{square feet} \][/tex]
4. Dimensions of the door: 5 feet wide and 7 feet tall
5. Area of the door:
[tex]\[ \text{Door area} = \text{width} \times \text{height} = 5 \, \text{ft} \times 7 \, \text{ft} = 35 \, \text{square feet} \][/tex]
6. Paintable area of the wall with the door:
[tex]\[ \text{Paintable area} = \text{Total area} - \text{Door area} = 144 \, \text{square feet} - 35 \, \text{square feet} = 109 \, \text{square feet} \][/tex]
### Wall with the Window
1. Height of the wall: 8 feet
2. Length of the wall: 15 feet
3. Total area of the wall:
[tex]\[ \text{Total area} = \text{height} \times \text{length} = 8 \, \text{ft} \times 15 \, \text{ft} = 120 \, \text{square feet} \][/tex]
4. Dimensions of the window: 6 feet wide and 3 feet tall
5. Area of the window:
[tex]\[ \text{Window area} = \text{width} \times \text{height} = 6 \, \text{ft} \times 3 \, \text{ft} = 18 \, \text{square feet} \][/tex]
6. Paintable area of the wall with the window:
[tex]\[ \text{Paintable area} = \text{Total area} - \text{Window area} = 120 \, \text{square feet} - 18 \, \text{square feet} = 102 \, \text{square feet} \][/tex]
### Comparison:
- Paintable area of the wall with the door: 109 square feet
- Paintable area of the wall with the window: 102 square feet
Since 109 square feet (paintable area of the wall with the door) is greater than 102 square feet (paintable area of the wall with the window):
The true statement about column A and column B is:
- A. The area in column A is greater.