Answer :
To solve the problem where a triangle was dilated by a scale factor of 4, and we are given that [tex]\(\overline{FD}\)[/tex] measures 12 units, we need to find the length of [tex]\(\overline{EF}\)[/tex] in the original triangle.
Here are the steps:
1. Understand that dilation by a scale factor changes all corresponding side lengths by that factor. So, if [tex]\(\overline{FD}\)[/tex] in the dilated triangle measures 12 units, we need to find the corresponding side length [tex]\(\overline{EF}\)[/tex] in the original triangle before dilation.
2. Given that the scale factor is 4, it means that every length in the original triangle is increased by a factor of 4 in the dilated triangle.
3. Therefore, to find the original length [tex]\(\overline{EF}\)[/tex], we need to divide the dilated side length [tex]\(\overline{FD}\)[/tex] by the scale factor. So, we do:
[tex]\[ \overline{EF} = \frac{\overline{FD}}{\text{scale factor}} \][/tex]
4. Substitute the known values:
[tex]\[ \overline{EF} = \frac{12}{4} = 3 \][/tex]
Therefore, the length of [tex]\(\overline{EF}\)[/tex] in the original triangle is 3 units. Since none of the provided answers (6, 9, 12, 16) match, it's important to cross-check the problem setup. Given the provided numerical answer, the length should specifically be:
[tex]\[ \overline{EF} = 3 \text{ units} \][/tex]
Thus, the choices listed do not include the correct value of [tex]\(\overline{EF}\)[/tex] based on the given information.
---
If this discrepancy arises from a misunderstanding of the problem or potential other details not specified, it's crucial to revisit exactly what is being asked or confirm all given values and relations in the problem.
Here are the steps:
1. Understand that dilation by a scale factor changes all corresponding side lengths by that factor. So, if [tex]\(\overline{FD}\)[/tex] in the dilated triangle measures 12 units, we need to find the corresponding side length [tex]\(\overline{EF}\)[/tex] in the original triangle before dilation.
2. Given that the scale factor is 4, it means that every length in the original triangle is increased by a factor of 4 in the dilated triangle.
3. Therefore, to find the original length [tex]\(\overline{EF}\)[/tex], we need to divide the dilated side length [tex]\(\overline{FD}\)[/tex] by the scale factor. So, we do:
[tex]\[ \overline{EF} = \frac{\overline{FD}}{\text{scale factor}} \][/tex]
4. Substitute the known values:
[tex]\[ \overline{EF} = \frac{12}{4} = 3 \][/tex]
Therefore, the length of [tex]\(\overline{EF}\)[/tex] in the original triangle is 3 units. Since none of the provided answers (6, 9, 12, 16) match, it's important to cross-check the problem setup. Given the provided numerical answer, the length should specifically be:
[tex]\[ \overline{EF} = 3 \text{ units} \][/tex]
Thus, the choices listed do not include the correct value of [tex]\(\overline{EF}\)[/tex] based on the given information.
---
If this discrepancy arises from a misunderstanding of the problem or potential other details not specified, it's crucial to revisit exactly what is being asked or confirm all given values and relations in the problem.