A triangle was dilated by a scale factor of 4. If [tex]\tan a ^{\circ}=\frac{4}{3}[/tex] and [tex]\overline{FD}[/tex] measures 12 units, how long is [tex]\overline{EF}[/tex]?

A. [tex]\overline{EF}=6[/tex] units
B. [tex]\overline{EF}=9[/tex] units
C. [tex]\overline{EF}=12[/tex] units
D. [tex]\overline{EF}=16[/tex] units



Answer :

To solve the problem where a triangle was dilated by a scale factor of 4, and we are given that [tex]\(\overline{FD}\)[/tex] measures 12 units, we need to find the length of [tex]\(\overline{EF}\)[/tex] in the original triangle.

Here are the steps:

1. Understand that dilation by a scale factor changes all corresponding side lengths by that factor. So, if [tex]\(\overline{FD}\)[/tex] in the dilated triangle measures 12 units, we need to find the corresponding side length [tex]\(\overline{EF}\)[/tex] in the original triangle before dilation.

2. Given that the scale factor is 4, it means that every length in the original triangle is increased by a factor of 4 in the dilated triangle.

3. Therefore, to find the original length [tex]\(\overline{EF}\)[/tex], we need to divide the dilated side length [tex]\(\overline{FD}\)[/tex] by the scale factor. So, we do:

[tex]\[ \overline{EF} = \frac{\overline{FD}}{\text{scale factor}} \][/tex]

4. Substitute the known values:

[tex]\[ \overline{EF} = \frac{12}{4} = 3 \][/tex]

Therefore, the length of [tex]\(\overline{EF}\)[/tex] in the original triangle is 3 units. Since none of the provided answers (6, 9, 12, 16) match, it's important to cross-check the problem setup. Given the provided numerical answer, the length should specifically be:

[tex]\[ \overline{EF} = 3 \text{ units} \][/tex]

Thus, the choices listed do not include the correct value of [tex]\(\overline{EF}\)[/tex] based on the given information.

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If this discrepancy arises from a misunderstanding of the problem or potential other details not specified, it's crucial to revisit exactly what is being asked or confirm all given values and relations in the problem.