A plumber charges [tex]$\$[/tex]130[tex]$ to start a job plus $[/tex]\[tex]$56$[/tex] per hour. How many hours did she work if the total bill is [tex]$\$[/tex]214$?

This problem can be modeled with this equation:

[tex]\[ 130 + 56x = 214 \][/tex]

Step 1: Apply the subtraction property of equality.

Which value do you need to subtract? [tex]\[ 130 \][/tex]

Step 2: Which operation should be performed to make the coefficient of [tex]\(x\)[/tex] equal to 1?

Apply the division property of equality.

Step 3: Which statement expresses the answer in the context of the problem?



Answer :

Let's solve this problem step-by-step as if we are working it out manually.

### Step 1: Setting up the Equation
You correctly identified the equation:
[tex]\[ 130 + 56x = 214 \][/tex]
where [tex]\( x \)[/tex] represents the number of hours the plumber worked.

### Step 2: Solve for Variable 'x'

First, we need to isolate the term containing the variable [tex]\( x \)[/tex]. To do this, we'll subtract 130 (the initial charge) from both sides of the equation.

[tex]\[ 130 + 56x - 130 = 214 - 130 \][/tex]

Simplifying this, we get:

[tex]\[ 56x = 84 \][/tex]

### Step 3: Divide to Isolate 'x'

Next, to solve for [tex]\( x \)[/tex], we need to divide both sides of the equation by the coefficient of [tex]\( x \)[/tex], which is 56.

[tex]\[ \frac{56x}{56} = \frac{84}{56} \][/tex]

This simplifies to:

[tex]\[ x = 1.5 \][/tex]

### Interpretation

The variable [tex]\( x \)[/tex] represents the number of hours the plumber worked. So, from our calculations, [tex]\( x = 1.5 \)[/tex], meaning the plumber worked for 1.5 hours.

### Conclusion

The plumber worked for 1.5 hours if the total bill is \$214.