Answered

```latex
\begin{tabular}{|c|c|c|c|c|c|}
\hline
\begin{tabular}{l}
Number of \\
washers
\end{tabular} & Trial & \multicolumn{2}{|c|}{\begin{tabular}{l}
[tex]$t_1$[/tex] (s)
\end{tabular}} & Time [tex]$t_2$[/tex] (s) & \begin{tabular}{l}
[tex]$\epsilon_2$[/tex] (s)
\end{tabular} \\
\hline
\multirow{2}{}{1 washer} & Trial \#1 & 2.24 & \multirow{2}{}{Average} & 3.16 & \multirow{2}{*}{Average} \\
\cline{2-3} \cline{5-5}
& Trial \#2 & 2.21 & 2.23 & 3.08 & 3.13 \\
\hline
\end{tabular}

What is the average velocity of this car over the first 0.25 m?

What is the average velocity of the car over the second 0.25 m?

[tex]\[
\boxed{ \text{ } m / s \text{ } }
\][/tex]
```



Answer :

GinnyAnswer
Sure! Let's analyze the problem step-by-step, based on the provided data.

### Given data:
1. Time for the first 0.25 meters (0.25m):
- [tex]\( t_1 \)[/tex] for Trial 1: [tex]\( 2.24 \)[/tex] s
- [tex]\( t_1 \)[/tex] for Trial 2: [tex]\( 2.21 \)[/tex] s
- [tex]\( t_1 \)[/tex] for Trial 3: [tex]\( 2.23 \)[/tex] s
- Average [tex]\( t_1 \)[/tex]: [tex]\( 2.23 \)[/tex] s

2. Time for the second 0.25 meters (0.25m):
- [tex]\( t_2 \)[/tex] for Trial 1: [tex]\( 3.16 \)[/tex] s
- [tex]\( t_2 \)[/tex] for Trial 2: [tex]\( 3.08 \)[/tex] s
- [tex]\( t_2 \)[/tex] for Trial 3: [tex]\( 3.15 \)[/tex] s
- Average [tex]\( t_2 \)[/tex]: [tex]\( 3.13 \)[/tex] s

### Calculating average velocity for each segment:
#### 1. Average velocity for the first 0.25 meters:
The average time for the first 0.25 meters (average [tex]\( t_1 \)[/tex]) is [tex]\( 2.23 \)[/tex] seconds.

[tex]\[ \text{Average Velocity}_1 = \frac{\text{Distance}}{\text{Average Time}} = \frac{0.25 \, \text{m}}{2.23 \, \text{s}} \approx 0.112 \, \text{m/s} \][/tex]

#### 2. Average velocity for the second 0.25 meters:
The average time for the second 0.25 meters (average [tex]\( t_2 \)[/tex]) is [tex]\( 3.13 \)[/tex] seconds.

[tex]\[ \text{Average Velocity}_2 = \frac{\text{Distance}}{\text{Average Time}} = \frac{0.25 \, \text{m}}{3.13 \, \text{s}} \approx 0.080 \, \text{m/s} \][/tex]

### Final results:
- The average velocity of the car over the first 0.25 meters is approximately [tex]\( 0.112 \, \text{m/s} \)[/tex].
- The average velocity of the car over the second 0.25 meters is approximately [tex]\( 0.080 \, \text{m/s} \)[/tex].

Feel free to ask if you have any more questions!