What is a point-slope equation of the line with slope -12 that goes through the point [tex]\((5, 3)\)[/tex]?

A. [tex]\(y + 3 = -12(x + 5)\)[/tex]

B. [tex]\(y - 3 = 12(x - 5)\)[/tex]

C. [tex]\(y + 3 = 12(x + 5)\)[/tex]

D. [tex]\(y - 3 = -12(x - 5)\)[/tex]



Answer :

To determine the point-slope form of the line with a given slope of -12 that passes through the point (5, 3), we need to use the point-slope formula.

The point-slope form of a linear equation is given by:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
where [tex]\((x_1, y_1)\)[/tex] is a point on the line and [tex]\(m\)[/tex] is the slope of the line.

Here, the point given is (5, 3), so [tex]\((x_1, y_1) = (5, 3)\)[/tex], and the slope [tex]\(m\)[/tex] is -12. Plugging these values into the point-slope formula gives us:
[tex]\[ y - 3 = -12(x - 5) \][/tex]

Thus, the equation of the line in point-slope form is:
[tex]\[ y - 3 = -12(x - 5) \][/tex]

This matches option D.

Therefore, the correct choice is:
D. [tex]\(y - 3 = -12(x - 5)\)[/tex]