Sure! Let's analyze the given chemical equation to identify the acid, base, and their conjugates:
[tex]\[ HCl + C_5H_5N \rightleftharpoons Cl^{-} + HC_5H_5N^{+} \][/tex]
Here's how we can break this down:
1. HCl: In this reaction, HCl donates a proton (H+) to C_5H_5N. A substance that donates a proton is classified as an acid.
2. C_5H_5N: This compound accepts a proton from HCl, which makes it a base because a base is a substance that accepts a proton.
3. Cl⁻: After HCl donates its proton, it becomes Cl⁻. Since Cl⁻ is formed by the loss of a proton from an acid (HCl), Cl⁻ is the conjugate base.
4. HC_5H_5N⁺: When C_5H_5N accepts a proton, it becomes HC_5H_5N⁺. This is the conjugate acid because it is formed by the gain of a proton by a base (C_5H_5N).
So, the labels should be:
[tex]\[
\begin{array}{cccc}
\text{HCl} & + & \text{C}_5\text{H}_5\text{N} & \rightleftharpoons \text{Cl}^- & + & \text{HC}_5\text{H}_5\text{N}^+ \\
\text{acid} & & \text{base} & & \text{conjugate base} & \text{conjugate acid}
\end{array}
\][/tex]
Finally, placing the labels into the equation, we get:
[tex]\[
\boxed{\text{acid}} + \boxed{\text{base}} \rightleftharpoons \boxed{\text{conjugate base}} + \boxed{\text{conjugate acid}}
\][/tex]
So, the equation should look like:
[tex]\[ \boxed{\text{acid}} \ HCl + \boxed{\text{base}} \ C_5H_5N \rightleftharpoons \boxed{\text{conjugate base}} \ Cl^- + \boxed{\text{conjugate acid}} \ HC_5H_5N^+ \][/tex]
