Hannah and Claire each have a chicken coop with 6 hens. Let [tex]$H$[/tex] represent the total number of eggs the hens lay on a randomly chosen day in Hannah's coop, and let [tex]$C$[/tex] represent the total number of eggs the hens lay on a randomly chosen day in Claire's coop. The two distributions are displayed in the table and histograms.

\begin{tabular}{|c|c|c|c|c|c|c|c|}
\hline
\begin{tabular}{c}
Number of \\
Eggs
\end{tabular} & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline
[tex]$P(H)$[/tex] & 0.02 & 0.03 & 0.07 & 0.12 & 0.30 & 0.28 & 0.18 \\
\hline
[tex]$P(C)$[/tex] & 0.05 & 0.09 & 0.14 & 0.23 & 0.21 & 0.16 & 0.12 \\
\hline
\end{tabular}

Which statement correctly compares the centers of the distributions?

A. Hannah's hens appear to lay more eggs, on average, than Claire's hens.

B. Hannah's hens are expected to lay 4 eggs in a day; Claire's hens are expected to lay 3 eggs in a day.

C. Hannah's hens appear to lay fewer eggs, on average, than Claire's hens.

D. Claire's hens appear to lay about the same number of eggs, on average, as Hannah's hens.



Answer :

To compare the centers of the distributions represented by [tex]\( H \)[/tex] and [tex]\( C \)[/tex], we need to calculate their expected values. The expected value (or mean) of a discrete random variable is calculated by summing the products of each value the variable can take and the probability of that value.

### Calculating the Expected Number of Eggs for Hannah's Hens

The probability distribution for the number of eggs laid by Hannah's hens [tex]\( P(H) \)[/tex] is given as:

[tex]\[ \begin{array}{|c|c|c|c|c|c|c|c|} \hline \text{Number of Eggs} & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text{Probability} & 0.02 & 0.03 & 0.07 & 0.12 & 0.30 & 0.28 & 0.18 \\ \hline \end{array} \][/tex]

To find the expected value [tex]\( E(H) \)[/tex], we calculate:

[tex]\[ E(H) = \sum ( \text{Number of Eggs} \times \text{Probability}) \][/tex]

[tex]\[ E(H) = 0 \times 0.02 + 1 \times 0.03 + 2 \times 0.07 + 3 \times 0.12 + 4 \times 0.30 + 5 \times 0.28 + 6 \times 0.18 \][/tex]

[tex]\[ E(H) = 0 + 0.03 + 0.14 + 0.36 + 1.20 + 1.40 + 1.08 = 4.21 \][/tex]

Thus, the expected number of eggs laid by Hannah's hens in a day is 4.21.

### Calculating the Expected Number of Eggs for Claire's Hens

The probability distribution for the number of eggs laid by Claire's hens [tex]\( P(C) \)[/tex] is given as:

[tex]\[ \begin{array}{|c|c|c|c|c|c|c|c|} \hline \text{Number of Eggs} & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text{Probability} & 0.05 & 0.09 & 0.14 & 0.23 & 0.21 & 0.16 & 0.12 \\ \hline \end{array} \][/tex]

To find the expected value [tex]\( E(C) \)[/tex], we calculate:

[tex]\[ E(C) = \sum ( \text{Number of Eggs} \times \text{Probability}) \][/tex]

[tex]\[ E(C) = 0 \times 0.05 + 1 \times 0.09 + 2 \times 0.14 + 3 \times 0.23 + 4 \times 0.21 + 5 \times 0.16 + 6 \times 0.12 \][/tex]

[tex]\[ E(C) = 0 + 0.09 + 0.28 + 0.69 + 0.84 + 0.80 + 0.72 = 3.42 \][/tex]

Thus, the expected number of eggs laid by Claire's hens in a day is 3.42.

### Conclusion

Based on the calculated expected values:
- Hannah's hens are expected to lay, on average, 4.21 eggs per day.
- Claire's hens are expected to lay, on average, 3.42 eggs per day.

Thus, the correct statement is:
- "Hannah's hens appear to lay more eggs, on average, than Claire's hens."