Answer :
Certainly! Let's go through the steps to identify which option explains how System A was transformed into System B.
First, let's look at System A:
[tex]\[ \begin{array}{l} -x - 2y = 7 \\ 5x - 6y = -3 \end{array} \][/tex]
And now, let’s look at the resulting System B:
[tex]\[ \begin{array}{l} -x - 2y = 7 \\ -16y = 32 \end{array} \][/tex]
To figure out how we got from System A to System B, we need to manipulate the second equation [tex]\(5x - 6y = -3\)[/tex] in System A.
1. Multiply the first equation by 5:
[tex]\[ 5 \cdot (-x - 2y) = 5 \cdot 7 \implies -5x - 10y = 35 \][/tex]
2. Add this result to the second equation [tex]\(5x - 6y = -3\)[/tex]:
[tex]\[ (5x - 6y) + (-5x - 10y) = -3 + 35 \][/tex]
This simplifies to:
[tex]\[ 5x - 6y - 5x - 10y = 32 \implies -16y = 32 \][/tex]
This shows that the second equation in System B results from replacing the second equation in System A with the sum of that equation and the first equation multiplied by 5.
Therefore, the correct option is:
D. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by 5. The solution to system B will be the same as the solution to system A.
First, let's look at System A:
[tex]\[ \begin{array}{l} -x - 2y = 7 \\ 5x - 6y = -3 \end{array} \][/tex]
And now, let’s look at the resulting System B:
[tex]\[ \begin{array}{l} -x - 2y = 7 \\ -16y = 32 \end{array} \][/tex]
To figure out how we got from System A to System B, we need to manipulate the second equation [tex]\(5x - 6y = -3\)[/tex] in System A.
1. Multiply the first equation by 5:
[tex]\[ 5 \cdot (-x - 2y) = 5 \cdot 7 \implies -5x - 10y = 35 \][/tex]
2. Add this result to the second equation [tex]\(5x - 6y = -3\)[/tex]:
[tex]\[ (5x - 6y) + (-5x - 10y) = -3 + 35 \][/tex]
This simplifies to:
[tex]\[ 5x - 6y - 5x - 10y = 32 \implies -16y = 32 \][/tex]
This shows that the second equation in System B results from replacing the second equation in System A with the sum of that equation and the first equation multiplied by 5.
Therefore, the correct option is:
D. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by 5. The solution to system B will be the same as the solution to system A.