12. A book with a mass of 5 kg is pushed off a table with a velocity of [tex]$2 \, m/s$[/tex]. What is its momentum?

A. [tex]$7 \, kg \cdot m/s$[/tex]

B. [tex][tex]$10 \, kg \cdot m/s$[/tex][/tex]

C. [tex]$15 \, kg \cdot m/s$[/tex]

D. [tex]$3 \, kg \cdot m/s$[/tex]



Answer :

To determine the momentum of the book, we use the formula for momentum:

[tex]\[ p = mv \][/tex]

where
- [tex]\( p \)[/tex] represents momentum,
- [tex]\( m \)[/tex] represents mass, and
- [tex]\( v \)[/tex] represents velocity.

Given:
- The mass ([tex]\( m \)[/tex]) of the book is [tex]\( 5 \)[/tex] kg.
- The velocity ([tex]\( v \)[/tex]) of the book is [tex]\( 2 \)[/tex] m/s.

Let's plug in the values into the formula:

[tex]\[ p = 5 \, \text{kg} \times 2 \, \text{m/s} \][/tex]

Now, perform the multiplication:

[tex]\[ p = 10 \, \text{kg} \cdot \text{m/s} \][/tex]

Thus, the momentum of the book is:

[tex]\[ 10 \, \text{kg} \cdot \text{m/s} \][/tex]

So, the correct answer is:

B. [tex]\( 10 \, \text{kg} \cdot \text{m/s} \)[/tex]