How will the circumference of the circle change if it is dilated by a scale factor of 4?

A. The circumference will be 4 times greater than the original.
B. The circumference will be 16 times greater than the original.
C. The circumference will be [tex]$\frac{1}{4}$[/tex] the original.
D. The circumference will be [tex]$\frac{1}{16}$[/tex] the original.



Answer :

To answer the question of how the circumference of a circle changes when it is dilated by a scale factor of 4, let's carefully analyze the properties of dilations and circles.

1. Understanding dilation: When a geometric shape is dilated by a scale factor [tex]\( k \)[/tex], every linear dimension of the shape (such as lengths, widths, and perimeters) is multiplied by that scale factor [tex]\( k \)[/tex].

2. Circle and its circumference: The circumference [tex]\( C \)[/tex] of a circle is directly proportional to its radius [tex]\( r \)[/tex], given by the formula:
[tex]\[ C = 2 \pi r \][/tex]
Here, [tex]\( \pi \)[/tex] is a constant and [tex]\( r \)[/tex] is the radius.

3. Effect of dilation on the radius: When the circle is dilated by a scale factor of 4, the new radius [tex]\( r' \)[/tex] becomes:
[tex]\[ r' = 4r \][/tex]

4. Effect of dilation on the circumference: Since the circumference is directly proportional to the radius, if the radius is multiplied by 4, the circumference will also be multiplied by 4:
[tex]\[ C' = 2 \pi r' = 2 \pi (4r) = 4 (2 \pi r) = 4C \][/tex]

Therefore, the circumference after dilation will be 4 times greater than the original circumference.

To summarize:

- The circumference will be 4 times greater than the original.

So the correct answer is:
- The circumference will be 4 times greater than the original.