Answer :

Answer:

[tex]\huge\boxed{+6}[/tex]

Explanation:

Given compound:

H₂SO₄

Hydrogen (H) usually has an oxidation state of +1.

Oxygen (O) usually has an oxidation state of -2.

According to the rules of oxidation state:

For a neutral compound, the net oxidation state adds up to zero.

Let the oxidation state of sulfur be x.

So,

2(+1) + x + 4(-2) = 0

+2 + x - 8 = 0

x - 6 = 0

Add 6 to both sides

x = +6

So, the oxidation state of sulfur in H₂SO₄ is +6.

[tex]\rule[2]{225}{2}[/tex]

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