To determine the solubility of potassium chlorate ([tex]\(KClO_3\)[/tex]) at 40°C, we follow these steps:
1. Define Solubility:
The solubility of a substance in a solvent is the amount of solute that can dissolve in a given volume of solvent to form a saturated solution at a specific temperature.
2. Given Data:
- Volume of saturated solution: [tex]\(100 \, \text{cm}^3\)[/tex]
- Mass of salt recovered upon evaporation: [tex]\(14 \, \text{g}\)[/tex]
3. Solubility Calculation:
Solubility is typically expressed in grams of solute per 100 cm³ of solvent. In this case, since we obtained 14 grams of [tex]\(KClO_3\)[/tex] from evaporating 100 cm³ of the solution, the solubility (S) is directly determined by the amount of salt recovered from the saturated solution.
4. Solubility Formula:
Solubility ([tex]\(S\)[/tex]) is calculated as:
[tex]\[
S = \frac{\text{mass of solute}}{\text{volume of solvent}}
\][/tex]
5. Substitute Given Values:
[tex]\[
S = \frac{14 \, \text{g}}{100 \, \text{cm}^3}
\][/tex]
6. Calculate Solubility:
[tex]\[
S = 0.14 \, \text{g/cm}^3
\][/tex]
So, the solubility of [tex]\(KClO_3\)[/tex] at 40°C is [tex]\(0.14 \, \text{g/cm}^3\)[/tex].
