To find the solubility of [tex]\( KClO_3 \)[/tex] in grams per 100 cm[tex]\(^3\)[/tex] of water at [tex]\( 40^{\circ}C \)[/tex], we can follow these steps:
1. Understand the given information:
- A saturated solution of [tex]\( KClO_3 \)[/tex] at [tex]\( 40^{\circ}C \)[/tex] is given.
- The volume of the saturated solution is [tex]\( 100 \, \text{cm}^3 \)[/tex].
- After evaporation of the solution, [tex]\( 14 \, \text{g} \)[/tex] of [tex]\( KClO_3 \)[/tex] is recorded.
2. Know the relationship:
- Solubility is defined as the maximum amount of solute (in grams) that can dissolve in [tex]\( 100 \, \text{cm}^3 \)[/tex] of solvent (water in this case) to form a saturated solution at a specific temperature.
3. Set up the problem:
- We need to calculate the solubility of [tex]\( KClO_3 \)[/tex] in [tex]\( 100 \, \text{cm}^3 \)[/tex] of water at [tex]\( 40^{\circ}C \)[/tex].
4. Use the given data to find solubility:
We are given the mass of [tex]\( KClO_3 \)[/tex] obtained after evaporation is [tex]\( 14 \, \text{g} \)[/tex]. Since this mass is from [tex]\( 100 \, \text{cm}^3 \)[/tex] of solution, solubility directly corresponds to the mass of [tex]\( KClO_3 \)[/tex] in [tex]\( 100 \, \text{cm}^3 \)[/tex] of the solution.
Therefore, the solubility of [tex]\( KClO_3 \)[/tex] at [tex]\( 40^{\circ}C \)[/tex] in [tex]\( 100 \, \text{cm}^3 \)[/tex] of water is:
[tex]\[ \text{Solubility} = 14 \, \text{g} \, \text{per} \, 100 \, \text{cm}^3 \][/tex]
So, the solubility of [tex]\( KClO_3 \)[/tex] at [tex]\( 40^{\circ}C \)[/tex] is [tex]\( 14 \, \text{g/100 cm}^3 \)[/tex].
