A number when divided by 558 leaves a remainder of 42. What remainder would be obtained by dividing the same number by 18?

A. 28
B. 21
C. 9
D. 7



Answer :

Let's solve the problem step-by-step:

1. First, consider the number [tex]\( n \)[/tex]. According to the problem, when [tex]\( n \)[/tex] is divided by 558, it leaves a remainder of 42. This means we can write:
[tex]\[ n = 558k + 42 \][/tex]
for some integer [tex]\( k \)[/tex].

2. We need to find the remainder when this number [tex]\( n \)[/tex] is divided by 18.

3. Substitute the expression for [tex]\( n \)[/tex] into the division by 18:
[tex]\[ n = 558k + 42 \][/tex]
Find the remainder when [tex]\( 558k + 42 \)[/tex] is divided by 18. We can do this in parts.

4. First, find the remainder when [tex]\( 558k \)[/tex] is divided by 18. Since 558 is a multiple of 18:
[tex]\[ 558 = 18 \times 31 \][/tex]
This means that [tex]\( 558k \)[/tex] divided by 18 will leave no remainder, because it is already completely divisible by 18.

5. Next, consider the term 42. Find the remainder when 42 is divided by 18:
[tex]\[ 42 \div 18 = 2 \text{ R } 6 \][/tex]
Here, dividing 42 by 18 gives a quotient of 2 and a remainder of 6.

6. Therefore, the remainder when [tex]\( 558k + 42 \)[/tex] is divided by 18 is the same as the remainder when 42 is divided by 18, which is:
[tex]\[ 6 \][/tex]

So, the remainder when the number is divided by 18 is [tex]\( 6 \)[/tex].

The correct answer is [tex]\(\boxed{6}\)[/tex].