Find the area of a regular octagon with an apothem of 15 cm and a side length of 12.4 cm.

[tex]\[ \text{Area} = [?] \, \text{cm}^2 \][/tex]



Answer :

To find the area of a regular octagon with an apothem of 15 cm and a side length of 12.4 cm, you can follow these steps:

1. Understand the properties of the octagon:
- An octagon has 8 sides.
- The apothem is the perpendicular distance from the center of the octagon to one of its sides.

2. Calculate the perimeter of the octagon:
- The perimeter [tex]\( P \)[/tex] is given by the product of the number of sides and the length of each side.
[tex]\[ P = \text{number of sides} \times \text{side length} \][/tex]
- For our octagon:
[tex]\[ P = 8 \times 12.4 \, \text{cm} \][/tex]
- This simplifies to:
[tex]\[ P = 99.2 \, \text{cm} \][/tex]

3. Use the formula for the area of a regular polygon:
- The formula to calculate the area [tex]\( A \)[/tex] of a regular polygon is:
[tex]\[ A = \frac{1}{2} \times P \times a \][/tex]
- Where [tex]\( P \)[/tex] is the perimeter and [tex]\( a \)[/tex] is the apothem.

4. Substitute the known values into the formula:
- Here, [tex]\( P = 99.2 \, \text{cm} \)[/tex] and [tex]\( a = 15 \, \text{cm} \)[/tex].
[tex]\[ A = \frac{1}{2} \times 99.2 \, \text{cm} \times 15 \, \text{cm} \][/tex]
- This simplifies to:
[tex]\[ A = \frac{1}{2} \times 1488 \, \text{cm}^2 \][/tex]
- Which further simplifies to:
[tex]\[ A = 744 \, \text{cm}^2 \][/tex]

Hence, the area of the regular octagon is [tex]\( 744 \, \text{cm}^2 \)[/tex].