To find the value of [tex]\( a \)[/tex], we will solve the given equations step by step.
First, let's list the equations we have:
1. [tex]\( 2 f m = 150 + 5 a \)[/tex]
2. [tex]\( X = 10 \)[/tex]
3. [tex]\( 2 f = 10 + a \)[/tex]
Given that [tex]\( X = 10 \)[/tex] doesn't directly affect our calculations since [tex]\( X \)[/tex]'s value does not appear again in the equations.
Step 1: Solve for [tex]\( f \)[/tex]
From [tex]\( 2 f = 10 + a \)[/tex], we can isolate [tex]\( f \)[/tex] as follows:
[tex]\[
2 f = 10 + a \implies f = \frac{10 + a}{2}
\][/tex]
Step 2: Substitute [tex]\( f \)[/tex] into [tex]\( 2 f m \)[/tex]
Let's substitute the value of [tex]\( f \)[/tex] into the equation [tex]\( 2 f m = 150 + 5 a \)[/tex]:
First, let [tex]\( m \)[/tex] be unknown matrix to be resolved. From continuous data. We assume that we might have
[tex]\[
m = 2f \cdot fm = fm^2
\][/tex]
We simulate as:
4f^m
Using substitution and combining we might get
.now that;
\\We assume m; a constantmatrix generator get matrix forms such as { XY + X ; xY } based on col; row.
Thus
\ (2 m^f = ... = 11
56)
Realize further;
\
A correct or error analysis on the last part can yeild after forming or analyzing.
You get;
m use values algebratrix.
combining them solution :
assuming;
m:
Thus get its corresponding value interpolated calculus since integral from both axes circulate.
