To solve this problem, we need to calculate the pressure exerted by the block on the tabletop. Pressure is defined as the force applied per unit area.
Here's the step-by-step solution:
1. Calculate the Force:
- The force exerted by the block is due to its weight, which can be calculated using the formula:
[tex]\[
\text{Force} = \text{mass} \times \text{gravitational acceleration}
\][/tex]
- Given:
[tex]\[
\text{mass} = 7.5 \text{ kg}
\][/tex]
[tex]\[
\text{gravitational acceleration} = 9.8 \text{ m/s}^2
\][/tex]
- Therefore:
[tex]\[
\text{Force} = 7.5 \text{ kg} \times 9.8 \text{ m/s}^2 = 73.5 \text{ N}
\][/tex]
2. Calculate the Pressure:
- Pressure is defined as force per unit area:
[tex]\[
\text{Pressure} = \frac{\text{Force}}{\text{Area}}
\][/tex]
- Given that the bottom surface area of the block is:
[tex]\[
\text{Area} = 0.6 \text{ m}^2
\][/tex]
- Therefore:
[tex]\[
\text{Pressure} = \frac{73.5 \text{ N}}{0.6 \text{ m}^2} = 122.5 \text{ Pa}
\][/tex]
So, the pressure exerted by the block on the tabletop is 122.5 Pa. Thus, the correct answer is:
[tex]\[
\text{B. 122.5 Pa}
\][/tex]
