Mass of box [tex]\( A = 10 \)[/tex] grams; Mass of box [tex]\( B = 5 \)[/tex] grams; Mass of box [tex]\( C \)[/tex] is made of one [tex]\( A \)[/tex] and one [tex]\( B \)[/tex].

How many boxes of [tex]\( A \)[/tex] would be required to make 30 grams of [tex]\( C \)[/tex]? [tex]\(\square\)[/tex]



Answer :

To solve this problem, follow these steps:

1. Determine the mass of box C:
- Box C is composed of one box A and one box B.
- The mass of box A is 10 grams.
- The mass of box B is 5 grams.
- Therefore, the mass of box C is the sum of the masses of box A and box B.
[tex]\[ \text{Mass of box C} = 10\, \text{grams} + 5\, \text{grams} = 15\, \text{grams} \][/tex]

2. Calculate how many grams we need to achieve:
- We aim to make a total of 30 grams of box C.

3. Determine how many boxes of C are needed to reach 30 grams:
- Each box of C has a mass of 15 grams.
- To find out how many boxes of C are required to make 30 grams, divide 30 grams by the mass of one box of C.
[tex]\[ \text{Number of boxes of C needed} = \frac{30\, \text{grams}}{15\, \text{grams/box}} = 2\, \text{boxes} \][/tex]

4. Calculate how many boxes of A are needed:
- Each box of C is made of one box A.
- Since we need 2 boxes of C to make 30 grams, we need 2 boxes of A (one for each box of C).
[tex]\[ \text{Number of boxes of A needed} = 2 \][/tex]

Therefore, 2 boxes of A are required to make 30 grams of box C.