Select all the correct answers.

Which factors compose the least common denominator for this difference?
[tex]\[
\frac{11x}{x^2 + 4x - 12} - \frac{7}{2x^2 - 4x}
\][/tex]

A. [tex]\(2x\)[/tex]
B. [tex]\((x-6)\)[/tex]
C. [tex]\((x-2)\)[/tex]
D. [tex]\((x+6)\)[/tex]
E. [tex]\((x-4)\)[/tex]
F. [tex]\((x+2)\)[/tex]



Answer :

To solve this problem, let's begin by factoring each denominator in the given fractions.

Given fractions are:
[tex]\[ \frac{11x}{x^2 + 4x - 12} - \frac{7}{2x^2 - 4x} \][/tex]

We need to factor the denominators:

1. For the first fraction:
[tex]\[ x^2 + 4x - 12 \][/tex]
The factors of this quadratic expression are:
[tex]\[ (x - 2)(x + 6) \][/tex]

2. For the second fraction:
[tex]\[ 2x^2 - 4x \][/tex]
We can factor out the common factor of 2x:
[tex]\[ 2x(x - 2) \][/tex]

Now, to find the least common denominator (LCD), we need to collect all unique factors from the factored denominators.

From the first fraction:
[tex]\[ (x - 2), (x + 6) \][/tex]

From the second fraction:
[tex]\[ 2, x, (x - 2) \][/tex]

To form the LCD, we gather each unique factor:
[tex]\[ 2, x, (x - 2), (x + 6) \][/tex]

Thus, the factors that compose the Least Common Denominator (LCD) are:
[tex]\[ 2, x, (x - 2), (x + 6) \][/tex]

Therefore, the correct answers are:
[tex]\[ 2x, (x - 2), (x + 6) \][/tex]