To find the probability that a randomly selected car with no 4-wheel drive has third-row seats, we need to analyze the given two-way table.
The table provides the following information:
- The total number of cars that have no 4-wheel drive.
- The number of cars that have no 4-wheel drive and have third-row seats.
From the table:
- The total number of cars that have no 4-wheel drive is 40.
- The number of cars that have no 4-wheel drive and have third-row seats is 12.
The probability can be found using the formula for probability:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
Here, the number of favorable outcomes is the number of cars with no 4-wheel drive that have third-row seats, which is 12. The total number of outcomes is the total number of cars with no 4-wheel drive, which is 40.
So, the probability is:
[tex]\[ \text{Probability} = \frac{12}{40} = 0.3 \][/tex]
Thus, the probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\(0.3\)[/tex].
The correct answer is [tex]\(0.3\)[/tex].
