For each equation, choose the statement that describes its solution. If applicable, give the solution.

[tex]\[ -3(y+1) + 7y = 4(y+1) - 5 \][/tex]

A. No solution
B. [tex]\( y = \square \)[/tex]
C. All real numbers are solutions



Answer :

Let's solve the equation step-by-step.

We start with the given equation:
[tex]\[ -3(y + 1) + 7y = 4(y + 1) - 5 \][/tex]

Step 1: Distribute the constants inside the parentheses.
[tex]\[ -3(y + 1) = -3y - 3 \][/tex]
[tex]\[ 4(y + 1) = 4y + 4 \][/tex]

After distributing, our equation becomes:
[tex]\[ -3y - 3 + 7y = 4y + 4 - 5 \][/tex]

Step 2: Combine like terms on both sides of the equation.
[tex]\[ (-3y + 7y) - 3 = 4y + (4 - 5) \][/tex]
[tex]\[ 4y - 3 = 4y - 1 \][/tex]

Step 3: Isolate the variables on one side and constants on the other side.

Subtract [tex]\( 4y \)[/tex] from both sides:
[tex]\[ 4y - 3 - 4y = 4y - 1 - 4y \][/tex]
[tex]\[ -3 = -1 \][/tex]

Step 4: Notice that we end up with a false statement ([tex]\(-3 = -1\)[/tex]) which is clearly incorrect.

Since the equation results in a contradiction, there is no value of [tex]\( y \)[/tex] that can satisfy the equation.

Therefore, the solution to the equation is:
[tex]\[ \text{No solution} \][/tex]

Box the final answer:

[tex]\[ \boxed{\text{No solution}} \][/tex]