Sure, let's work through the steps of the question methodically.
1. Write the capacity of tank A in usual form:
The capacity of tank A is given as [tex]\(7.5 \times 10^4\)[/tex] liters.
To convert this scientific notation to usual form:
[tex]\[
7.5 \times 10^4 = 75,000 \text{ liters}
\][/tex]
Therefore, the capacity of tank A in usual form is 75,000 liters.
2. Find the total capacity of tank A and tank B:
The capacity of tank B is given as [tex]\(1.9375 \times 10^4\)[/tex] liters.
To find the total capacity of tanks A and B, add their capacities:
[tex]\[
7.5 \times 10^4 + 1.9375 \times 10^4 = 75,000 + 19,375 = 94,375 \text{ liters}
\][/tex]
Therefore, the total capacity of tanks A and B is 94,375 liters.
3. Determine how many tanks with capacity [tex]\(1.9375 \times 10^3\)[/tex] liters are required to store the total water:
Suppose we distribute the total water from both tank A and B into smaller tanks, each with a capacity of [tex]\(1.9375 \times 10^3\)[/tex] liters.
First, convert the smaller tank's capacity to usual form:
[tex]\[
1.9375 \times 10^3 = 1,937.5 \text{ liters}
\][/tex]
Now, find the number of such smaller tanks required:
[tex]\[
\text{Number of tanks required} = \frac{\text{Total capacity of tank A \& B}}{\text{Capacity of one smaller tank}} = \frac{94,375}{1,937.5} \approx 48.71
\][/tex]
Therefore, approximately 48.71 tanks are required to store the total water from tanks A and B.
