\begin{tabular}{|c|c|}
\hline
City & \begin{tabular}{c}
Temperature \\
[tex]$\left({ }^{\circ} F \right)$[/tex]
\end{tabular} \\
\hline
Miami & 79 \\
\hline
Louisville & 48 \\
\hline
Los Angeles & 66 \\
\hline
Montreal & -23 \\
\hline
Milwaukee & -15 \\
\hline
\end{tabular}

(a) How much lower was the 6 a.m. temperature in Montreal than in Miami?
[tex]$\square$[/tex] [tex]${ }^{\circ} F$[/tex] lower

(b) By noon, the temperature in Milwaukee had risen by [tex]$20^{\circ} F$[/tex]. What was the temperature there at noon?
[tex]$\square$[/tex] [tex]${ }^{\circ} F$[/tex]



Answer :

To solve the given problems, let's break down each part and find the answers step-by-step.

### Part (a)
We need to determine how much lower the temperature in Montreal was compared to Miami at 6 a.m.

1. Temperature in Montreal at 6 a.m.: [tex]\(-23^\circ F\)[/tex]
2. Temperature in Miami at 6 a.m.: [tex]\(79^\circ F\)[/tex]

To find how much lower Montreal's temperature was compared to Miami's temperature, we calculate the difference between Miami's temperature and Montreal's temperature.

[tex]\[ \text{Difference} = 79^\circ F - (-23^\circ F) \][/tex]

Subtracting a negative number is the same as adding the absolute value of that number:

[tex]\[ \text{Difference} = 79^\circ F + 23^\circ F = 102^\circ F \][/tex]

So, the temperature in Montreal was [tex]\(102^\circ F\)[/tex] lower than in Miami.

### Part (b)
We need to find the temperature in Milwaukee at noon, knowing that the temperature at 6 a.m. had risen by [tex]\(20^\circ F\)[/tex] by noon.

1. Temperature in Milwaukee at 6 a.m.: [tex]\(-15^\circ F\)[/tex]
2. Temperature rise: [tex]\(20^\circ F\)[/tex]

To find the temperature at noon, we add this rise to the 6 a.m. temperature:

[tex]\[ \text{Temperature at noon} = -15^\circ F + 20^\circ F = 5^\circ F \][/tex]

Thus, the temperature in Milwaukee at noon was [tex]\(5^\circ F\)[/tex].

### Summary of Answers
(a) The temperature in Montreal was [tex]\(102^\circ F\)[/tex] lower than in Miami.

(b) The temperature in Milwaukee at noon was [tex]\(5^\circ F\)[/tex].