Answered

What is the momentum of a 15 kg tire rolling down a hill at [tex]$3 \, \text{m/s}$[/tex]?

A. [tex]5 \, \text{kg} \cdot \text{m/s}[/tex]
B. [tex]18 \, \text{kg} \cdot \text{m/s}[/tex]
C. [tex]45 \, \text{kg} \cdot \text{m/s}[/tex]
D. [tex]60 \, \text{kg} \cdot \text{m/s}[/tex]



Answer :

GinnyAnswer
Sure, let's determine the momentum of a 15 kg tire rolling down a hill at a speed of 3 m/s.

Momentum ([tex]\(p\)[/tex]) is defined as the product of mass ([tex]\(m\)[/tex]) and velocity ([tex]\(v\)[/tex]). The formula to calculate momentum is:

[tex]\[ p = m \times v \][/tex]

In this problem, we are given:
- The mass [tex]\(m\)[/tex] of the tire is [tex]\(15 \ \text{kg}\)[/tex]
- The velocity [tex]\(v\)[/tex] of the tire is [tex]\(3 \ \text{m/s}\)[/tex]

Now, substitute the given values into the formula:

[tex]\[ p = 15 \ \text{kg} \times 3 \ \text{m/s} \][/tex]

[tex]\[ p = 45 \ \text{kg} \cdot \text{m/s} \][/tex]

So, the momentum of the tire is:

[tex]\[ \boxed{45 \ \text{kg} \cdot \text{m/s}} \][/tex]

The correct answer from the given options is [tex]\(45 \ \text{kg} \cdot \text{m/s}\)[/tex].