Answer :

To determine the coefficient of [tex]\( x \)[/tex] in the expression [tex]\( (x+3)^2 \)[/tex], let's expand the expression step by step.

1. The expression to expand is [tex]\( (x + 3)^2 \)[/tex].
2. We can use the binomial theorem or simply expand it directly using the distributive property (FOIL method).

Expanding [tex]\( (x + 3)^2 \)[/tex]:
[tex]\[ (x + 3)^2 = (x + 3)(x + 3) \][/tex]

3. Using the FOIL method (First, Outer, Inner, Last):
[tex]\[ (x + 3)(x + 3) = x \cdot x + x \cdot 3 + 3 \cdot x + 3 \cdot 3 \][/tex]

4. Perform each multiplication:
[tex]\[ x \cdot x = x^2 \][/tex]
[tex]\[ x \cdot 3 = 3x \][/tex]
[tex]\[ 3 \cdot x = 3x \][/tex]
[tex]\[ 3 \cdot 3 = 9 \][/tex]

5. Combine all these terms:
[tex]\[ x^2 + 3x + 3x + 9 \][/tex]

6. Combine like terms (the terms involving [tex]\( x \)[/tex]):
[tex]\[ x^2 + 6x + 9 \][/tex]

7. From the expanded expression [tex]\( x^2 + 6x + 9 \)[/tex], we observe that the coefficient of the term involving [tex]\( x \)[/tex] is [tex]\( 6 \)[/tex].

Thus, the coefficient of [tex]\( x \)[/tex] in [tex]\( (x + 3)^2 \)[/tex] is [tex]\( 6 \)[/tex].