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Use the periodic table to identify the element indicated by each electron configuration by typing in the chemical symbol for the element.

[tex]\[
\begin{array}{l}
1s^2 2s^2 2p^6 \\
1s^2 2s^2 2p^6 3s^2 3p^3 \\
1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 \\
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6 \\
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^3
\end{array}
\][/tex]



Answer :

GinnyAnswer
Sure! Let's identify the elements from their electron configurations step by step.

1. Electron Configuration: [tex]\(1s^2 2s^2 2p^6\)[/tex]:
- This configuration shows that the electrons fill up the [tex]\(1s\)[/tex], [tex]\(2s\)[/tex], and [tex]\(2p\)[/tex] orbitals.
- The total number of electrons is [tex]\(2 (1s) + 2 (2s) + 6 (2p) = 10\)[/tex].
- The element with atomic number 10 is Neon (Ne).

2. Electron Configuration: [tex]\(1s^2 2s^2 2p^6 3s^2 3p^3\)[/tex]:
- This configuration adds electrons in the [tex]\(3s\)[/tex] and [tex]\(3p\)[/tex] orbitals along with those before it.
- The total number of electrons is [tex]\(2 (1s) + 2 (2s) + 6 (2p) + 2 (3s) + 3 (3p) = 15\)[/tex].
- The element with atomic number 15 is Phosphorus (P).

3. Electron Configuration: [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^1\)[/tex]:
- This configuration adds electrons in the [tex]\(4s\)[/tex] orbital along with those before it.
- The total number of electrons is [tex]\(2 (1s) + 2 (2s) + 6 (2p) + 2 (3s) + 6 (3p) + 1 (4s) = 19\)[/tex].
- The element with atomic number 19 is Potassium (K).

4. Electron Configuration: [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6\)[/tex]:
- This configuration shows the addition of electrons in the [tex]\(4s\)[/tex] and [tex]\(3d\)[/tex] orbitals.
- The total number of electrons is [tex]\(2 (1s) + 2 (2s) + 6 (2p) + 2 (3s) + 6 (3p) + 2 (4s) + 6 (3d) = 26\)[/tex].
- The element with atomic number 26 is Iron (Fe).

5. Electron Configuration: [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^3\)[/tex]:
- This configuration shows electrons occupying the [tex]\(4s\)[/tex], [tex]\(3d\)[/tex], [tex]\(4p\)[/tex], [tex]\(5s\)[/tex], and [tex]\(4d\)[/tex] orbitals.
- The total number of electrons is [tex]\(2 (1s) + 2 (2s) + 6 (2p) + 2 (3s) + 6 (3p) + 2 (4s) + 10 (3d) + 6 (4p) + 2 (5s) + 3 (4d) = 41\)[/tex].
- The element with atomic number 41 is Niobium (Nb).

So, summarizing the elements for the given configurations:

- [tex]\(1s^2 2s^2 2p^6\)[/tex]: Ne (Neon)
- [tex]\(1s^2 2s^2 2p^6 3s^2 3p^3\)[/tex]: P (Phosphorus)
- [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^1\)[/tex]: K (Potassium)
- [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6\)[/tex]: Fe (Iron)
- [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^3\)[/tex]: Nb (Niobium)

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