Answer :

To find the determinant of the matrix [tex]\( \left|\begin{array}{lll}x^2 & x & 1 \\ x^3 & x^2 & x \\ x^4 & x^3 & x^2\end{array}\right| \)[/tex], we can proceed with the following steps:

1. Set Up the Matrix:
[tex]\[ A = \begin{pmatrix} x^2 & x & 1 \\ x^3 & x^2 & x \\ x^4 & x^3 & x^2 \end{pmatrix} \][/tex]

2. Calculate the Determinant:
The determinant of a [tex]\(3 \times 3\)[/tex] matrix [tex]\( A = \begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix} \)[/tex] is given by:
[tex]\[ \det(A) = a(ei - fh) - b(di - fg) + c(dh - eg) \][/tex]

3. Apply the Formula:
Let [tex]\( a = x^2 \)[/tex], [tex]\( b = x \)[/tex], [tex]\( c = 1 \)[/tex], [tex]\( d = x^3 \)[/tex], [tex]\( e = x^2 \)[/tex], [tex]\( f = x \)[/tex], [tex]\( g = x^4 \)[/tex], [tex]\( h = x^3 \)[/tex], and [tex]\( i = x^2 \)[/tex].

[tex]\[ \det(A) = x^2 \left( x^2 \cdot x^2 - x \cdot x^3 \right) - x \left( x^3 \cdot x^2 - x \cdot x^4 \right) + 1 \left( x^3 \cdot x^3 - x^2 \cdot x^4 \right) \][/tex]

4. Simplify Each Term:
- Calculate [tex]\( ei - fh \)[/tex]:
[tex]\[ ei = x^2 \cdot x^2 = x^4 \][/tex]
[tex]\[ fh = x \cdot x^3 = x^4 \][/tex]
[tex]\[ ei - fh = x^4 - x^4 = 0 \][/tex]

- Calculate [tex]\( di - fg \)[/tex]:
[tex]\[ di = x^3 \cdot x^2 = x^5 \][/tex]
[tex]\[ fg = x \cdot x^4 = x^5 \][/tex]
[tex]\[ di - fg = x^5 - x^5 = 0 \][/tex]

- Calculate [tex]\( dh - eg \)[/tex]:
[tex]\[ dh = x^3 \cdot x^3 = x^6 \][/tex]
[tex]\[ eg = x^2 \cdot x^4 = x^6 \][/tex]
[tex]\[ dh - eg = x^6 - x^6 = 0 \][/tex]

5. Combine the Results:
[tex]\[ \det(A) = x^2 \cdot 0 - x \cdot 0 + 1 \cdot 0 = 0 - 0 + 0 = 0 \][/tex]

Therefore, the value of the determinant of the given matrix is [tex]\(\boxed{0}\)[/tex].