Answer :

Certainly! Let's simplify the expression step-by-step:

[tex]\[ \left(\frac{x^{a+b}}{x^c}\right)^{a-b}\left(\frac{x^{b+c}}{x^a}\right)^{b-c}\left(\frac{x^{c+a}}{x^b}\right)^{c-a} \][/tex]

First, let's simplify the base of each term inside the parentheses:

### Simplifying Each Base Term

#### Term 1:
[tex]\[ \left(\frac{x^{a+b}}{x^c}\right)^{a-b} \][/tex]
Using the property of exponents [tex]\(\frac{x^m}{x^n} = x^{m-n}\)[/tex]:

[tex]\[ \left(x^{(a+b) - c}\right)^{a-b} = \left(x^{a+b-c}\right)^{a-b} \][/tex]

#### Term 2:
[tex]\[ \left(\frac{x^{b+c}}{x^a}\right)^{b-c} \][/tex]
Using the same exponent property:
[tex]\[ \left(x^{(b+c) - a}\right)^{b-c} = \left(x^{b+c-a}\right)^{b-c} \][/tex]

#### Term 3:
[tex]\[ \left(\frac{x^{c+a}}{x^b}\right)^{c-a} \][/tex]
Using the same exponent property:
[tex]\[ \left(x^{(c+a) - b}\right)^{c-a} = \left(x^{c+a-b}\right)^{c-a} \][/tex]

### Combining the Simplified Terms

Now we have:
[tex]\[ \left(x^{a+b-c}\right)^{a-b} \left(x^{b+c-a}\right)^{b-c} \left(x^{c+a-b}\right)^{c-a} \][/tex]

Applying the power of a power property [tex]\((x^m)^n = x^{mn}\)[/tex]:

#### Term 1:
[tex]\[ \left(x^{a+b-c}\right)^{a-b} = x^{(a+b-c)(a-b)} \][/tex]

#### Term 2:
[tex]\[ \left(x^{b+c-a}\right)^{b-c} = x^{(b+c-a)(b-c)} \][/tex]

#### Term 3:
[tex]\[ \left(x^{c+a-b}\right)^{c-a} = x^{(c+a-b)(c-a)} \][/tex]

So, the expression now is:
[tex]\[ x^{(a+b-c)(a-b)} \cdot x^{(b+c-a)(b-c)} \cdot x^{(c+a-b)(c-a)} \][/tex]

### Combining the Exponents

Using the property of exponents [tex]\(x^m \cdot x^n \cdot x^p = x^{m+n+p}\)[/tex]:

[tex]\[ x^{(a+b-c)(a-b) + (b+c-a)(b-c) + (c+a-b)(c-a)} \][/tex]

The simplified expression inside the exponent:

[tex]\[ (-a + b + c)(b - c) + (a - b + c)(-a + c) + (a + b - c)(a - b) \][/tex]

Hence, the simplified form of the given expression is:

[tex]\[ (x^{(-a + b + c)})^{(b - c)} \cdot (x^{(a - b + c)})^{(-a + c)} \cdot (x^{(a + b - c)})^{(a - b)} \][/tex]