Exam number: 700161RR

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Exam Instructions

Question 1 of 20:

Select the best answer for the question.

1. Solve this equation: [tex]$4y + 228 = 352$[/tex].

A. [tex]$y = 145$[/tex]



Answer :

To solve the equation [tex]\( 4y + 228 = 352 \)[/tex], we'll follow a step-by-step approach:

1. Start with the given equation:
[tex]\[ 4y + 228 = 352 \][/tex]

2. Isolate the term containing [tex]\( y \)[/tex]:
Subtract 228 from both sides of the equation to get rid of the constant term on the left side.
[tex]\[ 4y + 228 - 228 = 352 - 228 \][/tex]

3. Simplify both sides of the equation:
[tex]\[ 4y = 124 \][/tex]

4. Solve for [tex]\( y \)[/tex]:
Divide both sides of the equation by 4.
[tex]\[ \frac{4y}{4} = \frac{124}{4} \][/tex]
[tex]\[ y = 31 \][/tex]

So, the solution to the equation [tex]\( 4y + 228 = 352 \)[/tex] is [tex]\( y = 31 \)[/tex].

Thus, the best answer for the given question is:

A. [tex]\( y = 31 \)[/tex]