Answer :
Let's solve the given system of nonlinear equations:
1. [tex]\(\frac{2}{x} + \frac{3}{y} = -2\)[/tex]
2. [tex]\(\frac{3}{x} + \frac{4}{y} = \frac{5}{2}\)[/tex]
3. [tex]\(\frac{4}{x} - \frac{5}{y} = 1\)[/tex]
4. [tex]\(\frac{5}{x} - \frac{3}{y} = \frac{7}{4}\)[/tex]
The goal is to find values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that satisfy all four equations simultaneously. To solve these equations step-by-step, we can proceed as follows:
### Step 1: Rewrite each equation
We will rewrite each equation for clarity:
1. [tex]\(\frac{2}{x} + \frac{3}{y} = -2\)[/tex]
2. [tex]\(\frac{3}{x} + \frac{4}{y} = \frac{5}{2}\)[/tex]
3. [tex]\(\frac{4}{x} - \frac{5}{y} = 1\)[/tex]
4. [tex]\(\frac{5}{x} - \frac{3}{y} = \frac{7}{4}\)[/tex]
### Step 2: Substitution and Elimination Method
We can attempt to eliminate one of the variables by creating equivalent equations. First, let's express the terms [tex]\(\frac{1}{x}\)[/tex] and [tex]\(\frac{1}{y}\)[/tex] as new variables to make the system linear:
Let:
[tex]\[ u = \frac{1}{x} \][/tex]
[tex]\[ v = \frac{1}{y} \][/tex]
So, the equations become:
1. [tex]\(2u + 3v = -2\)[/tex]
2. [tex]\(3u + 4v = \frac{5}{2}\)[/tex]
3. [tex]\(4u - 5v = 1\)[/tex]
4. [tex]\(5u - 3v = \frac{7}{4}\)[/tex]
### Step 3: Checking the System for Consistency
We can rearrange the system and inspect for possible contradictions or solutions:
1. [tex]\(2u + 3v = -2\)[/tex]
2. [tex]\(3u + 4v = \frac{5}{2}\)[/tex]
3. [tex]\(4u - 5v = 1\)[/tex]
4. [tex]\(5u - 3v = \frac{7}{4}\)[/tex]
Given the complexity of this system and the method of substitution or elimination, such systems are typically solved using algebraic manipulation or numerical methods. However, in this case, we find that when trying to solve these equations simultaneously, there are no real or complex solutions that satisfy all four equations.
### Conclusion
The system of equations does not have any solution. Thus, there are no values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that satisfy all four provided equations simultaneously. The result is an empty set, meaning the system is inconsistent.
1. [tex]\(\frac{2}{x} + \frac{3}{y} = -2\)[/tex]
2. [tex]\(\frac{3}{x} + \frac{4}{y} = \frac{5}{2}\)[/tex]
3. [tex]\(\frac{4}{x} - \frac{5}{y} = 1\)[/tex]
4. [tex]\(\frac{5}{x} - \frac{3}{y} = \frac{7}{4}\)[/tex]
The goal is to find values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that satisfy all four equations simultaneously. To solve these equations step-by-step, we can proceed as follows:
### Step 1: Rewrite each equation
We will rewrite each equation for clarity:
1. [tex]\(\frac{2}{x} + \frac{3}{y} = -2\)[/tex]
2. [tex]\(\frac{3}{x} + \frac{4}{y} = \frac{5}{2}\)[/tex]
3. [tex]\(\frac{4}{x} - \frac{5}{y} = 1\)[/tex]
4. [tex]\(\frac{5}{x} - \frac{3}{y} = \frac{7}{4}\)[/tex]
### Step 2: Substitution and Elimination Method
We can attempt to eliminate one of the variables by creating equivalent equations. First, let's express the terms [tex]\(\frac{1}{x}\)[/tex] and [tex]\(\frac{1}{y}\)[/tex] as new variables to make the system linear:
Let:
[tex]\[ u = \frac{1}{x} \][/tex]
[tex]\[ v = \frac{1}{y} \][/tex]
So, the equations become:
1. [tex]\(2u + 3v = -2\)[/tex]
2. [tex]\(3u + 4v = \frac{5}{2}\)[/tex]
3. [tex]\(4u - 5v = 1\)[/tex]
4. [tex]\(5u - 3v = \frac{7}{4}\)[/tex]
### Step 3: Checking the System for Consistency
We can rearrange the system and inspect for possible contradictions or solutions:
1. [tex]\(2u + 3v = -2\)[/tex]
2. [tex]\(3u + 4v = \frac{5}{2}\)[/tex]
3. [tex]\(4u - 5v = 1\)[/tex]
4. [tex]\(5u - 3v = \frac{7}{4}\)[/tex]
Given the complexity of this system and the method of substitution or elimination, such systems are typically solved using algebraic manipulation or numerical methods. However, in this case, we find that when trying to solve these equations simultaneously, there are no real or complex solutions that satisfy all four equations.
### Conclusion
The system of equations does not have any solution. Thus, there are no values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that satisfy all four provided equations simultaneously. The result is an empty set, meaning the system is inconsistent.