Questions [tex]$105-110$[/tex]

105. The table below shows the number of times that different desserts were ordered at a restaurant.

\begin{tabular}{|c|c|}
\hline Dessert & Orders \\
\hline Panna cotta & 36 \\
\hline Brownie & 28 \\
\hline Chocolate soufflé & 22 \\
\hline Meringue & [tex]$a$[/tex] \\
\hline
\end{tabular}

If the probability that a customer orders meringue as a dessert is 0.312, what is the value of [tex]$a$[/tex]?

A. 33
B. 35
C. 37
D. 39



Answer :

To determine the value of [tex]\(a\)[/tex], which represents the number of times meringue was ordered, given that the probability of ordering meringue is 0.312, we follow these steps:

1. Calculate the total number of orders for the other desserts:
[tex]\[ \text{Total orders excluding meringue} = \text{Panna cotta} + \text{Brownie} + \text{Chocolate soufflé} \][/tex]
[tex]\[ = 36 + 28 + 22 \][/tex]
[tex]\[ = 86 \][/tex]

2. Let [tex]\( T \)[/tex] be the total number of orders including meringue. Therefore, the probability of ordering meringue can be expressed as:
[tex]\[ \frac{a}{T} = 0.312 \][/tex]

3. Express [tex]\( T \)[/tex] in terms of [tex]\( a \)[/tex] using the total orders:
[tex]\[ T = 86 + a \][/tex]

4. Substitute [tex]\( T \)[/tex] into the probability equation:
[tex]\[ \frac{a}{86 + a} = 0.312 \][/tex]

5. Solve for [tex]\( a \)[/tex] by isolating [tex]\( a \)[/tex]:
[tex]\[ a = 0.312 \times (86 + a) \][/tex]
[tex]\[ a = 26.832 + 0.312a \][/tex]
[tex]\[ a - 0.312a = 26.832 \][/tex]
[tex]\[ 0.688a = 26.832 \][/tex]
[tex]\[ a = \frac{26.832}{0.688} \][/tex]
[tex]\[ a \approx 39 \][/tex]

6. Match the calculated value of [tex]\( a \)[/tex] with the given choices: The value closest to 39 is indeed one of the choices provided.

Therefore, the value of [tex]\(a\)[/tex] is [tex]\(39\)[/tex].

The correct answer is [tex]\( \boxed{39} \)[/tex].

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