Solve the problem.

James wants to invest [tex]$\$[/tex]8,000[tex]$. He can invest the money at $[/tex]7.2\%[tex]$ simple interest for 30 years, or he can invest at $[/tex]7\%[tex]$ with interest compounded continuously for 30 years. Which option results in more total interest?

Formulas:
\[ I = P r t \]
\[ A = P e^{r t} \]

Options:
A. $[/tex]7.2\%[tex]$ simple interest results in more total interest.
B. $[/tex]7\%$ compounded continuously results in more total interest.



Answer :

Let's solve the problem of determining which investment option results in more total interest for James.

### Given Data:
- Principal amount [tex]\( P = \$8,000 \)[/tex]
- Simple interest rate [tex]\( r_{\text{simple}} = 7.2\% = 0.072 \)[/tex]
- Continuous compounding interest rate [tex]\( r_{\text{continuous}} = 7\% = 0.07 \)[/tex]
- Time [tex]\( t = 30 \)[/tex] years

### Simple Interest Calculation:
The formula for calculating simple interest is:
[tex]\[ I_{\text{simple}} = P \times r_{\text{simple}} \times t \][/tex]

Substituting the given values into the formula:
[tex]\[ I_{\text{simple}} = 8000 \times 0.072 \times 30 \][/tex]
[tex]\[ I_{\text{simple}} = 8000 \times 2.16 \][/tex]
[tex]\[ I_{\text{simple}} = 17280 \][/tex]

The total interest earned with a simple interest rate of [tex]\(7.2\%\)[/tex] over 30 years is \[tex]$17,280. ### Continuous Compounding Interest Calculation: The formula for calculating the amount with continuous compounding interest is: \[ A_{\text{continuous}} = P \times e^{(r_{\text{continuous}} \times t)} \] Where \( e \) is the base of the natural logarithm (approximately \(2.71828\)). Substituting the given values into the formula: \[ A_{\text{continuous}} = 8000 \times e^{(0.07 \times 30)} \] Calculate the exponent: \[ 0.07 \times 30 = 2.1 \] Now, calculate \( e^{2.1} \): \[ e^{2.1} \approx 8.16617 \] So: \[ A_{\text{continuous}} = 8000 \times 8.16617 \] \[ A_{\text{continuous}} \approx 65329.36 \] To find the interest earned: \[ I_{\text{continuous}} = A_{\text{continuous}} - P \] \[ I_{\text{continuous}} \approx 65329.36 - 8000 \] \[ I_{\text{continuous}} \approx 57329.36 \] The total interest earned with continuous compounding interest of \(7\%\) over 30 years is approximately \$[/tex]57,329.36.

### Comparison of Total Interest:
- Simple Interest: \[tex]$17,280 - Continuous Compounding Interest: \$[/tex]57,329.36

Thus, comparing the two amounts, we see that the interest earned from continuous compounding (\[tex]$57,329.36) is significantly higher than that earned from simple interest (\$[/tex]17,280).

### Conclusion:
Investing the \$8,000 at a [tex]\(7\%\)[/tex] interest rate compounded continuously for 30 years results in more total interest than investing at a [tex]\(7.2\%\)[/tex] simple interest rate for the same period.