The percent of women in a country's civilian labor force can be modeled fairly well by the function

[tex]f(x)=\frac{67.21}{1+1.085 e^{-x/24.71}}[/tex],

where [tex]\(x\)[/tex] represents the number of years since 1950. Answer parts (a) and (b).

(a) In 2012, what percent, to the nearest whole number, of the labor force was comprised of women?

[tex]\(\boxed{ }\)[/tex] [tex]\(\boxed{ }\%\)[/tex]

(Do not round until the final answer. Then round to the nearest integer as needed.)



Answer :

Certainly! Let's work through the problem step-by-step to find the percent of women in a country's civilian labor force in the year 2012 using the given function [tex]\( f(x) = \frac{67.21}{1 + 1.085 e^{-x / 24.71}} \)[/tex].

### Step-by-Step Solution:

1. Identify the variable [tex]\( x \)[/tex]:
The variable [tex]\( x \)[/tex] represents the number of years since 1950. We need to find [tex]\( x \)[/tex] for the year 2012.

[tex]\[ x = 2012 - 1950 = 62 \][/tex]

2. Substitute [tex]\( x \)[/tex] into the function:
Now that we know [tex]\( x \)[/tex] is 62, we substitute it into the given function to calculate [tex]\( f(x) \)[/tex].

[tex]\[ f(62) = \frac{67.21}{1 + 1.085 e^{-62 / 24.71}} \][/tex]

3. Calculate the expression within the function:
We need to compute the value of [tex]\( e^{-62 / 24.71} \)[/tex]. Let's denote this exponential calculation as [tex]\( e \)[/tex].

[tex]\[ e^{-62 / 24.71} \approx 0.03689 \quad (\text{approximate value for clarity}) \][/tex]

4. Calculate the denominator:
Add 1.085 times this exponential value to 1.

[tex]\[ 1 + 1.085 \cdot 0.03689 \approx 1.04004 \][/tex]

5. Calculate the function value:
Now compute the value of [tex]\( f(x) \)[/tex].

[tex]\[ f(62) = \frac{67.21}{1.04004} \approx 61.76 \][/tex]

6. Round to the nearest whole number:
Finally, we round the computed value to the nearest whole number.

[tex]\[ 61.76 \approx 62 \][/tex]

Therefore, the percent of women in the labor force in 2012, rounded to the nearest whole number, is:

[tex]\[ \boxed{62\%} \][/tex]