Find the expected value of the winnings from a game that has the following payout probability distribution:

[tex]\[
\begin{array}{c|ccccc}
\text{Payout }(\$) & 0 & 5 & 8 & 10 & 15 \\
\hline
\text{Probability} & 0.50 & 0.20 & 0.15 & 0.10 & 0.05 \\
\end{array}
\][/tex]

Round to the nearest hundredth.



Answer :

To find the expected value of the winnings from the given payout probability distribution, we can use the following steps:

1. Identify the Payouts and Probabilities:
[tex]\[ \begin{array}{c|ccccc} \text { Payout }(\$) & 0 & 5 & 8 & 10 & 15 \\ \hline \text { Probability } & 0.50 & 0.20 & 0.15 & 0.10 & 0.05 \\ \end{array} \][/tex]

2. Multiply Each Payout by Its Corresponding Probability:
- For the payout of \[tex]$0 with probability 0.50: \[ 0 \times 0.50 = 0 \] - For the payout of \$[/tex]5 with probability 0.20:
[tex]\[ 5 \times 0.20 = 1 \][/tex]
- For the payout of \[tex]$8 with probability 0.15: \[ 8 \times 0.15 = 1.2 \] - For the payout of \$[/tex]10 with probability 0.10:
[tex]\[ 10 \times 0.10 = 1 \][/tex]
- For the payout of \$15 with probability 0.05:
[tex]\[ 15 \times 0.05 = 0.75 \][/tex]

3. Sum All the Products to Get the Expected Value:
[tex]\[ 0 + 1 + 1.2 + 1 + 0.75 = 3.95 \][/tex]

4. Round the Expected Value to the Nearest Hundredth:
The sum we obtained is already to two decimal places, so no further rounding is needed.

Therefore, the expected value of the winnings from this game is:
[tex]\[ \boxed{3.95} \][/tex]