Which choice is equivalent to the fraction below when [tex]\(x \geq 2\)[/tex]?

Hint: Rationalize the denominator and simplify.

[tex]\[
\frac{4}{\sqrt{x-2}-\sqrt{x}}
\][/tex]

A. [tex]\(2(\sqrt{x}+\sqrt{x-2})\)[/tex]

B. [tex]\(-2(\sqrt{x}+\sqrt{x-2})\)[/tex]

C. [tex]\(2(\sqrt{x}-\sqrt{x-2})\)[/tex]

D. [tex]\(-2(\sqrt{x}-\sqrt{x-2})\)[/tex]



Answer :

To determine which choice is equivalent to the given fraction [tex]\(\frac{4}{\sqrt{x-2}-\sqrt{x}}\)[/tex], we first need to rationalize the denominator and then simplify the expression.

### Step-by-Step Solution:

1. Given Expression:
[tex]\[ \frac{4}{\sqrt{x-2} - \sqrt{x}} \][/tex]

2. Rationalize the Denominator:

To rationalize the denominator, we multiply both the numerator and the denominator by the conjugate of the denominator [tex]\(\sqrt{x-2} + \sqrt{x}\)[/tex]:
[tex]\[ \frac{4}{\sqrt{x-2} - \sqrt{x}} \times \frac{\sqrt{x-2} + \sqrt{x}}{\sqrt{x-2} + \sqrt{x}} \][/tex]

3. Multiply the Numerator and Denominator:

The numerator becomes:
[tex]\[ 4 \times (\sqrt{x-2} + \sqrt{x}) \][/tex]
The denominator is a difference of squares:
[tex]\[ (\sqrt{x-2} - \sqrt{x})(\sqrt{x-2} + \sqrt{x}) = (\sqrt{x-2})^2 - (\sqrt{x})^2 = (x-2) - x = -2 \][/tex]

4. Form the New Fraction:

The expression now simplifies to:
[tex]\[ \frac{4(\sqrt{x-2} + \sqrt{x})}{-2} \][/tex]

5. Simplifying Further:

Divide the numerator by [tex]\(-2\)[/tex]:
[tex]\[ \frac{4}{-2} \times (\sqrt{x-2} + \sqrt{x}) = -2(\sqrt{x-2} + \sqrt{x}) \][/tex]

6. Rewriting Simplified Expression:

[tex]\[ -2(\sqrt{x} + \sqrt{x-2}) \][/tex]

### Conclusion:

The simplified expression is:
[tex]\[ -2(\sqrt{x} + \sqrt{x-2}) \][/tex]

Therefore, the correct choice is:

Answer: B. [tex]\(-2(\sqrt{x} + \sqrt{x-2})\)[/tex]