Alright, let's break this down step by step for clarity:
1. Given Data:
- Mass of the block, [tex]\( m = 7.5 \)[/tex] kg
- Area of the bottom surface of the block, [tex]\( A = 0.6 \)[/tex] [tex]\( m^2 \)[/tex]
- Acceleration due to gravity, [tex]\( g = 9.8 \)[/tex] [tex]\( m/s^2 \)[/tex] (which is a standard value on Earth's surface)
2. Calculate the Force Exerted by the Block (Weight):
- The force exerted by the block is its weight, which can be calculated using the formula:
[tex]\[
\text{Weight} (F) = \text{mass} \times \text{gravity} = m \times g
\][/tex]
- Plugging in the values:
[tex]\[
F = 7.5 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 73.5 \, \text{N}
\][/tex]
3. Calculate the Pressure:
- Pressure is defined as the force applied per unit area, given by the formula:
[tex]\[
\text{Pressure} (P) = \frac{\text{Force} (F)}{\text{Area} (A)}
\][/tex]
- Plugging the calculated force and given area into the formula:
[tex]\[
P = \frac{73.5 \, \text{N}}{0.6 \, \text{m}^2} = 122.5 \, \text{Pa}
\][/tex]
4. Conclusion:
- The correct pressure exerted by the 7.5 kg block on the tabletop is [tex]\( 122.5 \)[/tex] Pa.
Therefore, the best answer is:
D. 122.5 Pa
